Question

At what distance is the electrostatic force between two electrons equal to the weight of one?

Answer 1

Answer:

5.08m

Explanation:

Charge on an electron=$-1.6\times 10^{-19}C$

Number of electrons=2

Mass of electron=$9.1\times 10^{-31}kg$

Weight of electron=mg

Where g=Acceleration due to gravity=9.8$m/s^2$

Using the formula

Weight of an electron=$9.1\times 10^{-31}\times 9.8$N

Force between two electrons =Weight of an electron

We know that

Electrostatic force =$k\frac{q_1q_2}{r^2}$

Where $q_1,q_2=$Charge

r=Distance between two charges

$k=9\times 10^9 Nm^2/C^2$

Using the formula

$9.1\times 10^{-31}\times 9.8=\frac{9\times 10^9(1.6\times 10^{-19})^2}{r^2}$

$r^2=\frac{9\times 10^9\times 2.56\times 10^{-38}}{9.1\times 10^{-31}\times 9.8}=25.8$

$r=\sqrt{25.8}=5.08m$

Hence, the distance between two electrons=5.08m