Answer:
The IR-A is the greatest energy per photon compare to that of IR-B.
Explanation:
Given that,
Wavelength of (IR-B)= 1400 nm
Wavelength of (IR-A)= 700 nm
We need to calculate the energy for IR-B
Using formula of energy
Put the value into the formula
The energy for IR-B is
We need to calculate the energy for IR-A
Using formula of energy
Put the value into the formula
The energy for IR-B is
Hence, The IR-A is the greatest energy per photon compare to that of IR-B.