Answer:
The magnitude of the magnetic force at 32.5⁰ to the field, is 2.22 F
Explanation:
Given;
magnitude of the magnetic force is F at 14.0⁰ with respect to the field.
To determine the magnitude of the magnetic force at 32.5⁰ to the field, we apply the following formula and solve with proportion;
f*Sin(14.0⁰) = F
f*Sin(32.5⁰) = ?

Therefore, the magnitude of the magnetic force at 32.5⁰ to the field, is 2.22 F
Answer:
Magnetic field, B = 0.199 T
Explanation:
It is given that,
Radius of circular loop, r = 11.7 cm = 0.117 m
Magnetic flux through the loop, 
The magnetic flux linked through the loop is :


Here, 

or


B = 0.199 T
So, the strength of the magnetic field is 0.199 T. Hence, this is the required solution.
Explanation:
Newton's second law:
∑F = ma
277 N − 245 N = (25 kg) a
a = 1.28 m/s²
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