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Ivahew [28]
3 years ago
15

"when you double the vehicle's weight, you will __________ the vehicle's stopping distance. "

Physics
1 answer:
Stolb23 [73]3 years ago
5 0

With same braking power you will be stopping faster on the original weight therefore the answer to fill the blank is increase. The stopping distance will increase as there'll be higher energy to dissipate than lighter cars applied with the braking force similar with that of the lighter car. Also the skid and drag will add to the distance as well as the inertia of the moving heavier vehicle would be greater as well.

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What sport is best for someone who is 5'10, 220 lbs?
tamaranim1 [39]
Football is because 5'10 is pretty tall and 220 would be hard to tackle
7 0
3 years ago
A resin tube and a PVC rod are both rubbed against styrofoam. Do
Ivan

The concepts of electrostatics allow us to find the result for the question about the electric forces in the two tubes is:

  • The tubes are attracted by having charges of different signs.

<h3>Electrostatics</h3>

Electrostatics studies the transfer of charge between bodies when they rub together, in generating the charges of the insulating bodies they are not mobile, so to transfer them from one body to another they must be in contact.

The force electric between charges is of two types:

  • Attractive. If the charges are of different signs.
  • Repulsive.  If  the charges are of the same sign.

The transferred charge depends on the bodies involved in the tables showns that the resin is positively charged when rubbed, the PVC acquires very little charge and polystyrene acquires a negative charge due to rubbing.

They indicate that the resin is rubbed with polystyrene, therefore the resin must acquire a positive charge and the polystyrene a negative charge.

Then the PVC is rubbed with the polystyrene, which initially we will assume neutral, the PVC does not acquire a charge and the polystyrenes acquires a negative charge, if the polystyrene is isolated from the ground, it shares this negative charge with the PVC, therefore the two materials remain with half of the negative charge.

Finally, we bring the resin, which is positively charged, closer to the PVC, which has a slight negative charge, therefore the two bodies must attract each other.

In conclusion using the concepts of electrostatics we can find the result for the question about the electric forces in the two tubes is:

  • The tubes are attracted by having charges of different signs.

Learn more about electrostatics here: brainly.com/question/17692887

6 0
3 years ago
An unknown mass of each of the following substances, initially at 23.0, absorbs 1910 of heat. The final temperature is recorded
babymother [125]
The data not given here is the specific heat capacity of pyrex glass equal to 0.75(J/g  °C). In this case, heat is equal to mass x specific heat capacity x temperature rise. Temperature difference is then equal to 1910 J / 0.75 J/g  °C / 23 g equal to 110. 75  <span>°C </span>
3 0
4 years ago
If you press as hard as you can against a brick wall until you begin to sweating and breathing hard did you do any work on the w
Reika [66]
No, as long as nothing moves you aren't doing work, since W=F.s. You have no s, so no W
4 0
3 years ago
In a certain region of space near earth's surface, a uniform horizontal magnetic field of magnitude B exists above a level defin
dmitriy555 [2]

Answer:

a) F = \frac{\pi d^2B^2lv}{16p}  

b) attached below

c) 0.037 m/s

Explanation:

<u>a) Determine the magnetic "drag" force acting  at the moment </u>

speed = v

first step: determine current in the loop

I = \frac{\pi d^2}{16pl} B lv   ----- ( 1 )

given that the current will induce force on the three sides of the loop found in the magnetic field

forces on vertical sides = + opposite

we will cancel out

hence equation 1 becomes

F = \frac{\pi d^2B^2lv}{16p}   ( according to Lenz law we can say that the direction of force is upwards and this force will slow down the decrease in flux )

<u>b) Determine the formula for Vt</u>

attached below

<u>c) Find Vt </u>

given :

B = 0.80 T

density of copper = 8.9 * 10^3 kg/m^3

resistivity of copper = 1.68 * 10^-8 Ωm

∴ Vt = 16 ( 8.9 * 10^3 kg/m^3 ) ( 1.68 * 10^-8 Ωm ) ( 9.8 m/s^2 ) / ( 0.08 T)^2

       = 0.037 m/s

3 0
3 years ago
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