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Ivahew [28]
3 years ago
15

"when you double the vehicle's weight, you will __________ the vehicle's stopping distance. "

Physics
1 answer:
Stolb23 [73]3 years ago
5 0

With same braking power you will be stopping faster on the original weight therefore the answer to fill the blank is increase. The stopping distance will increase as there'll be higher energy to dissipate than lighter cars applied with the braking force similar with that of the lighter car. Also the skid and drag will add to the distance as well as the inertia of the moving heavier vehicle would be greater as well.

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Which of the following would add more resistance? Check all that apply.
Blababa [14]

Answer:C. E.

Explanation:

4 0
2 years ago
If a force always acts perpendicular to an object's direction of motion, that force cannot change the object's kinetic energy.
Alina [70]

If a force always acts perpendicular to an object's direction of motion, that force cannot change the object's kinetic energy. It is a true statement .

Kinetic energy is the energy that an object possesses due to its motion. It is basically the energy of mass in motion. Kinetic energy can never be negative and it is a scalar quantity i.e. it provides only the magnitude and not the direction.

According to law of conservation of mechanical energy change in potential energy is equal and opposite to the change in the kinetic energy.

According to the principle of conservation of mechanical energy, The total mechanical energy of a system is conserved i.e., the energy can neither be created nor be destroyed; it can only be internally converted from one form to another if the forces doing work on the system are conservative in nature.

since, potential energy is stored in the form of work done

Work done = Fs cos (theta)

If force always acts perpendicular to an object's direction of motion

theta =   90 °

cos (90 ) = 0

Work done  = 0

since , there is no work done , hence kinetic energy will not change

To learn more about  kinetic energy here

brainly.com/question/12669551

#SPJ4

7 0
1 year ago
If a 340 N girl sits on a seesaw and is lifted 1.4 m in 1.6 s, how much work was done by the child on the other side?
blondinia [14]
In physics, work is defined as the total energy when an object is moved to a certain displacement by the application of external force. It is calculated by the expression W = Fd. For this case, the displacement is apparently zero, then there is no work in the system above.
4 0
3 years ago
An electron is released from rest at the negative plate of a parallel plate capacitor. The charge per unit area on each plate is
dmitriy555 [2]

Answer:

v = 1.15*10^{7} m/s

Explanation:

given data:

charge/ unit area= \sigma = 1.99*10^{-7} C/m^2

plate seperation = 1.69*10^{-2} m

we know that

electric field btwn the plates isE = \frac{\sigma}{\epsilon}

force acting on charge is F = q E

Work done by charge q id\Delta X =\frac{ q\sigma \Delta x}{\epsilon}

this work done is converted into kinectic enerrgy

\frac{1}{2}mv^2 =\frac{ q\sigma \Delta x}{\epsilon}

solving for v

v = \sqrt{\frac{2q\Delta x}{\epsilon m}

\epsilon = 8.85*10^{-12} Nm2/C2

v = \sqrt{\frac{2 1.6*10^{-19}1.99*10^{-7}*1.69*10^{-2}}{8.85*10^{-12} *9.1*10^{-31}}

v = 1.15*10^{7} m/s

8 0
3 years ago
What will occur when the trough of Wave A overlaps the trough of Wave B?
Pavel [41]
C because the wave length was longer
6 0
3 years ago
Read 2 more answers
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