Answer:
#2 you multiply the numbers
Explanation:
Answer:
Object B has a density of 2.5 g/cm³ which is greater than object A by 1 g/cm³
Explanation:
Since we know that the formula for density is d=m/v, we can divide each mass by its corresponding volume to find the densities
12/8=1.5
20/8=2.5
So we know that object B has a greater density than object A by 1 g/cm³ (gram per cubic centimeter). Also the standard unit for density is kilograms per cubic meter but I used gram per cubic centimeter since they were the given units. 1cm=100m, 1000g=1km
Answer:
160 Kg
Explanation:
This problem is solved by considering the mass balance. We know the density of water, which we will assume constant , the volume of water originally in the tank and the flows of water entering and leaving the tank.
Let m₀ mass of water initially in the tank
m₁ mass of water entering the tank and
m₂ mass of water exiting the tank
V tank volume
then
m₀ = D x V = 1000 Kg x 0.30 m³ = 300 Kg
m₁ = D Vwater in x time = 1000 Kg/m³ x 5 x 10⁻³ m /min x 20 min = 100 Kg
m₂ = D x Area Hose x Vel exit x time =
= 1000 Kg /m³ x 3.1416 x ( 0.02 m)² x 0.5 m/s x ( 20 min x 60 s/min)
= 240 Kg
mass of water initially + mass water in - mass water out =
(300 + 100 - 240) Kg = 160 Kg