Question

a ball of mass 4 kg is initially traveling at 2 meters per second and has a 5 Newton Force applied to it for 3 seconds what's the final velocity of the ball

Answer 1

$a=\frac{F}{m}=\frac{5N}{4kg}=1.2\frac{m}{s^2}$

$\Delta v = a \cdot t = 1.2 \frac{m}{s^2} \cdot 3 s = 3.6 \frac{m}{s}$

$v = v_0 + \Delta v = 2 + 3.6 = 5.6 \frac{m}{s}$