That information describes the plane's speed.
If he had also told them what direction they were flying, then
they would have been able to put the two pieces of information
together, and they would know the plane's velocity.
The period will be the same if the amplitude of the motion is increased to 2a
What is an Amplitude?
Amplitude refers to the maximum extent of a vibration or oscillation, measured from the position of equilibrium.
Here,
mass m is attached to the spring.
mass attached = m
time period = t
We know that,
The time period for the spring is calculated with the equation:

Where k is the spring constant
Now if the amplitude is doubled, it means that the distance from the equilibrium position to the displacement is doubled.
From the equation, we can say,
Time period of the spring is independent of the amplitude.
Hence,
Increasing the amplitude does not affect the period of the mass and spring system.
Learn more about time period here:
<u>brainly.com/question/13834772</u>
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1. Always be the bigger person
2. Violence is never the answer
3. Don’t fight fire with fire
Answer:

Explanation:
The question, translated, is:
- <em>A steel ball rolls and falls off the edge of a table from 4ft above the floor. If you hit the ground 5ft from the base of the table, what was your initial horizontal velocity?</em>
<em />
<h2>Solution</h2>
<em />
This is a projectile motion, for which, the equations that you will need are:


<u />
<u>1. Calculate the time that it takes the ball to fall 4ft</u>

<u />
<u>2. Calculate the horizontal velocity:</u>

Answer:
d. 6/5 M.
Explanation:
let the angular velocity = 
the radius of sphere (r) = 
moment of inertia of solid sphere
= 
rotational K.E of solid sphere= 
= 
we represent the mass of hallow sphere= 
moment of inertia of solid sphere
= 
rotational K.E of hollow sphere= 
= 
NOW,the kinetic energy of solid sphere= 1/2 kinetic energy of hallow sphere
=![1/2 [2/5 M(D/2)^2 ]\omega^2= 1/2 (1/2 (2/3 M_{hs}(D/2)^2 )\omega^2 }](https://tex.z-dn.net/?f=1%2F2%20%5B2%2F5%20M%28D%2F2%29%5E2%20%5D%5Comega%5E2%3D%201%2F2%20%281%2F2%20%282%2F3%20M_%7Bhs%7D%28D%2F2%29%5E2%20%29%5Comega%5E2%20%7D)
2/5M= 1/3
= 3(2/5M)
= 6/5 M