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NeTakaya
2 years ago
11

According to Ohm's law, which is stated as I = V + R, which two sentences are true?

Physics
1 answer:
Novay_Z [31]2 years ago
7 0

So, If the resistance decreases, then the current increases. Assume voltage is constant.

If the voltage increases, then the current increases. Assume resistance is constant.

Explanation:

According to the ohm's law; I = V/R;

  • If the resistance decreases the current increases assuming that the voltage is constant
  • if the voltage increases, then the current increases assuming that the resistance is constant.

Based on Ohm's law, we know that the current through a metallic conductor is directly proportional to the voltage across the ends.

From the relationship;

                 I = \frac{V}{R}

        we see that  V = IR

These equations affirms that

  • If the resistance decreases the current increases assuming that the voltage is constant based on the second equation

  • if the voltage increases, then the current increases assuming that the resistance is constant based on the first equation.

learn more:

Electric circuit brainly.com/question/10421964

#learnwithBrainly

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That information describes the plane's speed. 
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they would have been able to put the two pieces of information
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6 0
3 years ago
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A mass m is attached to an ideal massless spring. When this system is set in motion with amplitude a, it has a period t. What is
Luden [163]

The period will be the same if the amplitude of the motion is increased to 2a

What is an Amplitude?

Amplitude refers to the maximum extent of a vibration or oscillation, measured from the position of equilibrium.

Here,

mass m is attached to the spring.

mass attached = m

time period = t

We know that,

The time period for the spring is calculated with the equation:

T = 2\pi \sqrt{\frac{m}{k} }

Where k is the spring constant

Now if the amplitude is doubled, it means that the distance from the equilibrium position to the displacement is doubled.

From the equation, we can say,

Time period of the spring is independent of the amplitude.

Hence,

Increasing the amplitude does not affect the period of the mass and spring system.

Learn more about time period here:

<u>brainly.com/question/13834772</u>

#SPJ4

7 0
2 years ago
Describe three ways that adults continue to guide children's emotions during the school-age
wolverine [178]
1. Always be the bigger person
2. Violence is never the answer
3. Don’t fight fire with fire
6 0
3 years ago
Una bola de acero rueda y cae por el borde de una mesa desde 4ft por encima del piso. Si golpea el suelo a 5ft de la base de la
ycow [4]

Answer:

     \large\boxed{\large\boxed{10ft/s}}

Explanation:

The question, translated, is:

  • <em>A steel ball rolls and falls off the edge of a table from 4ft above the floor. If you hit the ground 5ft from the base of the table, what was your initial horizontal velocity?</em>

<em />

<h2>Solution</h2>

<em />

This is a projectile motion, for which, the equations that you will need are:

    V_x_0= V_x=x\cdot t

     y=y_0+Vy_o\cdot t-g\cdot t^2/2

<u />

<u>1. Calculate the time that it takes the ball to fall 4ft</u>

    0=4ft-g\cdot t^2/2\\\\t^2=2\times 4ft/( 32.174ft/s^2)=0.24865s^2\\\\t=0.4986s

<u />

<u>2. Calculate the horizontal velocity:</u>

     V_x_0= V_x=x\cdot t\\\\V_x_0=5ft/0.4986s=10.027ft/s\approx 10ft/s

3 0
3 years ago
At any angular speed, a certain uniform solid sphere of diameter D has half as much rotational kinetic energy as a certain unifo
Trava [24]

Answer:

d. 6/5 M.

Explanation:

let the angular velocity =  \omega

the radius of sphere (r) = \frac{D}{2}

moment of inertia of solid sphere I_s = 2/5 M(\frac{D}{2})^2

rotational K.E of solid sphere= \frac{1}{2}* I_s* \omega ^2

=  \frac{1}{2} * 2/5 M(\frac{D}{2})^2 * \omega^2

we represent the mass of hallow sphere= M_{hs}

moment of inertia of solid sphereI_{ss} = 2/3 M_{hs}(\frac{D}{2})^2

rotational K.E of hollow sphere= \frac{1}{2}* I_{ss} * \omega^2

= 1/2 *2/3 M_{hs}(\frac{D}{2})^2* \omega^2

NOW,the kinetic energy of solid sphere= 1/2 kinetic energy of hallow sphere

=1/2 [2/5 M(D/2)^2 ]\omega^2= 1/2 (1/2 (2/3 M_{hs}(D/2)^2 )\omega^2 }

2/5M= 1/3 M_{hs}

M_{hs} = 3(2/5M)

M_{hs} = 6/5 M

7 0
3 years ago
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