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bonufazy [111]
3 years ago
8

GO FAST / WILL MARK BRAINLIEST / WILL GIVE THANKS / WILL GIVE 5 STARS

Chemistry
1 answer:
Nikitich [7]3 years ago
7 0
<h2>question  1</h2>

Mg  + 2HCl→ MgCl2 + H2

after balancing the coefficient for H2   is 1

<em><u>explanation </u></em>

since 1  is in front of H2  it is the coefficient for H2


question  2

 the reaction is single replacement

<u><em>explanation</em></u>

  • because  single replacement  occurs when one element  replaces another.  
  • for  the reaction of  Mg + 2HCl→MgCl2 +H2   Chlorine  

<h2>  Question  3</h2>

The   coefficient  of  H2  is 3

<em><u>explanation</u></em>

  • from  the balanced chemical reaction
  • that is  N2 +3H2 →2NH3  the coefficient  in  front of H2  is   3
<h2 /><h2>  question  4</h2>

N2 + 3H2 → 2NH3  is  a  synthesis  reaction

<u><em>explanation; </em></u>

Synthesis reaction  occurs  when two or more  reactants combine  to form a single product.

  • N2  reacted with  H2  to form   NH3 (ammonia) hence  it is  an example of synthesis reaction.

<h2>question 5</h2>
  1. The sign  that shows that a chemical reaction  has occurred  is    color change, change  in temperature  and  formation of a  gas (bubble)

color change  change in temperature, formation  of  precipitate  and formation  of  a gas(bubble)  is always   an indicator of an occurrence of a chemical  change.

<h2>Question 6</h2>

H2S is not  a strong acid

<u><em>explanation</em></u>

  • strong acid undergo a complete electrolysis  when dissociate in water  for example  HNO3  
  • weak acid  undergo  a partial electrolysis  when dissociate in water   for example  H2S

<h2>question 7</h2>

feels slippery  is not  a property of an acid

<u><em>explanation</em></u>

  • feel  slippery is an example of a  base
  •  The properties of an acid are
  1. sour taste
  2. changes the color of an indicator
  3. usually react with metal among  others
<h2>  Question   8</h2>

detergent with a PH of about  10  is a  <u><em>basic</em></u>

<em><u>explanation</u></em>

  • Base has    a Ph  which range  from 7.1 to  14
  • since  the detergent  has a PH of 10 is a basic
<h2>Question 9</h2>

The balanced chemical equation  for the synthesis  of NaBr is

2Na  + Br2 →2 NaBr

<u><em>explanation</em></u>

 This is because the  equation obey the law of mas  conversation

   for  example it has  2 atoms of  Na   in both reactant and product side

<h2>Question 10</h2>

 reacts with metals  is not  a common  property of  a base

 <u><em>Explanation</em></u>

  • base has  
  1. bitter taste,
  2. feels slippery
  3. turn red litmus paper blue  among others
<h2>  question  11</h2>

Hydrochloric acid have  a PH   in  0-6 range

<u><em>explanation</em></u>

  • HCl  is a strong  acid  
  •  acid has a PH  which are below PH  of 7  hence HCl  has a PH which range from 0-6

<h2>Question 12</h2>

A brand  shampoo  which has a PH between  5 -6 is  a weak  acid

  •    generally acid  has  a PH below   7
  • weak  acid  has a PH of between  5 -6  therefore  brand  shampoo  is a weak  acid
<h2>question 13</h2>

The PH  that indicate  a  solution  of a  base is a PH of 12

 <em><u>Explanation</u></em>

  • base  has a PH  which range between 7-14, hence  a  PH of 12   indicate that it is a  Base
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1.36 × 10³ mL of water.

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We can utilize the dilution equation. Recall that:

\displaystyle M_1V_1= M_2V_2

Where <em>M</em> represents molarity and <em>V</em> represents volume.

Let the initial concentration and unknown volume be <em>M</em>₁ and <em>V</em>₁, respectively. Let the final concentration and required volume be <em>M</em>₂ and <em>V</em>₂, respectively. Solve for <em>V</em>₁:

\displaystyle \begin{aligned} (2.50\text{ M})V_1 &= (0.800\text{ M})(2.00\text{ L}) \\ \\ V_1 & = 0.640\text{ L} \end{aligned}

Therefore, we can begin with 0.640 L of the 2.50 M solution and add enough distilled water to dilute the solution to 2.00 L. The required amount of water is thus:
\displaystyle 2.00\text{ L} - 0.640\text{ L} = 1.36\text{ L}

Convert this value to mL:
\displaystyle 1.36\text{ L} \cdot \frac{1000\text{ mL}}{1\text{ L}} = 1.36\times 10^3\text{ mL}

Therefore, about 1.36 × 10³ mL of water need to be added to the 2.50 M solution.

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