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3 years ago

Which produces more energy:

Physics

1 answer:

Leya [2.2K]3 years ago

3 0

Answer:

a) uranium

b) deuterium

Explanation:

For the first question, you can actually know this by simple logic. The nucleus of Ucranium, has more energy than a pair of deuterium. Ucranium has a mass number and atomic mass higher than deuterium, therefore, when you do a fission with ucranium in it's nucleous, this would be in energy higher than the deuterium.

However, in terms of mass only, the fissioning of 1 gram of Deuterium will produce more energy than 1 gram of uranium, basically because deuterium is lighter and has a lower molecular weight than ucranium. This means that because of this lower molecular weight, in 1 gram of deuterium will contain more number of atoms than in 1 g of uranium. The interaction with these atoms, will produce more energy than the energy produced by uranium.

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3 years ago

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You wish to produce an emf of 41.0 mV using an inductor whose inductance is 13.0 H. You start with a current of 1.50 mA through

Molodets [167]

Answer:

The current through the inductor at the end of 2.60s is 9.7 mA.

Explanation:

Given;

emf of the inductor, V = 41.0 mV

inductance of the inductor, L = 13 H

initial current in the inductor, I₀ = 1.5 mA

change in time, Δt = 2.6 s

The emf of the inductor is given by;

$V = L\frac{di}{dt} \\\\V = \frac{L(I_1-I_o)}{dt} \\\\L(I_1-I_o) = V*dt\\\\I_1-I_o = \frac{V*dt}{L}\\\\I_1 = \frac{V*dt}{L} + I_o\\\\I_1 = \frac{41*10^{-3}*2.6}{13} +1.5*10^{-3}\\\\I_1 = 8.2*10^{-3} + 1.5*10^{-3}\\\\I_1 = 9.7 *10^{-3} \ A\\\\ I_1 = 9.7 \ mA$

Therefore, the current through the inductor at the end of 2.60 s is 9.7 mA.

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