Answer:
a) speed when Jack sees the pot : 12.92 meters per second
b) height difference 163.115 meters
Explanation:
First to calculate te initial speed we use the acceleration formula:
a= v1-v0/t
Acceleration being gravity's acceleration (9.8 m/s^2)
v1 being the speed when Jill sees the pot
v0 when Jack sees it
and t the time between
Solving for v0 it would be
v1 - a*t = v0
replacing

For the second question we use the position formula setting y0 and t0 as the position and time when jack sees the pot. (and setting the positive axis downward I.E. one meter below jack would be 1m not -1m)
The formula is

replacing

1. pulling tug of war
2. monkey swinging from vine
3. arm wrestle
S=Vt
110=V(72)
110/72=V
V=1.527m/s
Answer:
3.1 m/s
Explanation:
First, find the time it takes for the cat to land. Take down to be positive.
Given:
Δy = 0.61 m
v₀ = 0 m/s
a = 9.81 m/s²
Find: t
Δy = v₀ t + ½ at²
(0.61 m) = (0 m/s) t + ½ (9.81 m/s²) t²
t = 0.353 s
Now find the horizontal velocity needed to travel 1.1 m in that time.
Given:
Δx = 1.1 m
a = 0 m/s²
t = 0.353 s
Find: v₀
Δx = v₀ t + ½ at²
(1.1 m) = v₀ (0.353 s) + ½ (0 m/s²) (0.353 s)²
v₀ = 3.1 m/s