Answer:
A force that objects exert, stopping solid objects from passing through each other aka contact.
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Answer:
a) t =12[s]; b) x = 348[m]
Explanation:
We can solve this problem using the following kinematics equations:
a)
where:
vf = final velocity = 12 [m/s]
vo= initial velocity = 6 [m/s]
a = acceleration = 0.5[m/s^2]
t = time [s]
Now clearing the time t, we have:
b)
We can calculate the displacement for the first 12 [s] then using the equation for the constant velocity we can calculate the other displacement for the 20[s].
The we can calculate the second displacement for the constant velocity:
x = x1 + x2
x = 108 + 240
x = 348[m]
In the case of work (and also energy), the standard metric unit is the Joule (abbreviated J). One Joule is equivalent to one Newton of force causing a displacement of one meter. In other words, The Joule is the unit of work (if that helped any!)
Answer:
The answer to your question is below
Explanation:
Data
light speed = 300 000 km/s
a) Express it in scientific notation
to do it, we just move the decimal point 5 places to the left
300 000 = 3.0 x 10 ⁵ km/s
b) Convert this value to meters per hour
(300 000 km/s)(1000 m/1 km)(3600 s/1 h) = 300000x1000x3600 / 1x1x1
= 1.08 x 10¹² m/h
c) What distance in centimeters does light travel in 1 s?
data
v = 300 000 km/s
d = ?
t = 1 s
formula v = d/t we clear distance d = vxt
d = 300000 x 1 = 300000 km
d = 300000000 m = 30000000000 cm