Answer:
1.84 kJ (kilojoules)
Explanation:
A specific heat of 0.46 J/g Cº means that it takes 0.46 Joules of energy to raise the temperature of 1 gram of iron by 1 Cº.
If we want to heat 50 g of iron from 20° C to 100° C, we can make the following calculation:
Heat = (specific heat)*(mass)*(temp change)
Heat = (0.46 J/g Cº)*(50g)*(100° C - 20° C)
[Note how the units cancel to yield just Joules]
Heat = 1840 Joules, or 1.84 kJ
[Note that the number is positive: Energy is added to the system. If we used cold iron to cool 50g of 100° C water, the temperature change would be (Final - Initial) or (20° C - 100° C). The number is -1.84 kJ: the negative means heat was removed from the system (the iron).
Answer:
has free electrons
Explanation:
A conductor has free electrons while an insulator does not. Free electrons are electrons which are not bounded tightly to their parent atoms, and are free to move given the right conditions (ie. a strong EM field).
Answer:
The energy stored is 1.4 x 10^-9 J.
Explanation:
Side of square, L = 10 cm = 0.1 m
Distance, d = 2 mm = 0.002 m
Electric field, E = 4000 V/m
The energy stored in the capacitor is
![U = 0.5 C V^2](https://tex.z-dn.net/?f=U%20%3D%200.5%20C%20V%5E2)
The capacitance is given by
![C = \frac{\varepsilon o A}{d}\\\\So \\\\U = 0.5\frac{\varepsilon o A}{d}\times E^2 d^2\\\\U = 0.5\times 8.85\times 10^{-12}\times 0.1\times 0.1\times 4000\times 4000\times 0.002\\\\U = 1.4\times10^{-9} J](https://tex.z-dn.net/?f=C%20%3D%20%5Cfrac%7B%5Cvarepsilon%20o%20A%7D%7Bd%7D%5C%5C%5C%5CSo%20%5C%5C%5C%5CU%20%3D%200.5%5Cfrac%7B%5Cvarepsilon%20o%20A%7D%7Bd%7D%5Ctimes%20E%5E2%20d%5E2%5C%5C%5C%5CU%20%3D%200.5%5Ctimes%208.85%5Ctimes%2010%5E%7B-12%7D%5Ctimes%200.1%5Ctimes%200.1%5Ctimes%204000%5Ctimes%204000%5Ctimes%200.002%5C%5C%5C%5CU%20%3D%201.4%5Ctimes10%5E%7B-9%7D%20J)
Answer:
66.6 or it could be 66.66 one of those
Explanation: