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2 years ago

What distance is required for a train to stop if its initial velocity is 23 m/s and its

Physics

1 answer:

Varvara68 [4.7K]2 years ago

7 0

-- The train starts at 23 m/s and slows down by 0.25 m/s every second.

So it'll take (23/0.25) = 92 seconds to stop.

-- Its average speed during that time will be (1/2)(23+0) = 11.5 m/s

-- Moving at an average speed of 11.5 m/s for 92 sec, the train will cover

(11.5 m/s) x (92 sec) = 1,058 meters .

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Explanation:

t = Time taken

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Time the rocket will keep going up after the engines shut off is 13.06 seconds.

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The distance the rocket will keep going up after the engines shut off is 836.05 m

Total distance traveled by the rocket in the upward direction is 1180+836.05 = 2016.05 m

The rocket will fall from this height

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Time taken by the rocket to fall from maximum height is 20.29 seconds

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