All categories

3 years ago

What distance is required for a train to stop if its initial velocity is 23 m/s and its

Physics

1 answer:

Varvara68 [4.7K]3 years ago

7 0

-- The train starts at 23 m/s and slows down by 0.25 m/s every second.

So it'll take (23/0.25) = 92 seconds to stop.

-- Its average speed during that time will be (1/2)(23+0) = 11.5 m/s

-- Moving at an average speed of 11.5 m/s for 92 sec, the train will cover

(11.5 m/s) x (92 sec) = <em>1,058 meters</em> .

You might be interested in

A ball is dropped from a height of 1.30 m. How long does it take to hit the ground? WebAssign will check your answer for the cor

Citrus2011 [14]

Answer:

a) t= 0.515 s

b) vf= 5.047 m/s

Explanation:

Because ball move with uniformly accelerated movement we apply the following formulas:

d= v₀t+ (1/2)*g*t² Formula (1)

vf= v₀+gt Formula (2)

Where:

d:displacement in meters (m)

t : time in seconds (s)

v₀: initial speed in m/s

vf: final speed in m/s

g: acceleration due to gravity in m/s²

Known data

v₀=0

d= 1.30 m

g= 9.8 m/s²

Problem development

a) We appy the formula 1 to calculate the time (t):

d= v₀t+ (1/2)*g*t²

1.30= 0+ (1/2)* (9.8)*t²

1.30=4.9*t²

t²=1.30/4.9

$t=\sqrt{\frac{1.3}{4.9} }$

t= 0.515 s

b) We appy the formula 2 to calculate the final speed (vf):

vf= v₀+gt

vf= 0+(9.8)*(0.515)

vf= 5.047 m/s

8 0

3 years ago

If you answer this I will give you brainliest whoever answers first!!!

rusak2 [61]

Explanation:

this graph show the decrease in velocity with time

at time t=0 velocity is 40 m/sec

at time t=12sec velocity is decreases from 40 to 10 m/s

so the acceleration of the object at time=12 sec is

a=v/t

a=Δv/t

Δv=v1-v2=40-10=30 m/s

a=30/12=2.5 m/s^2

4 0

3 years ago

A white pool ball of mass 1.0 kg moving at 10 m/s collides with

solniwko [45]

The velocity of the red ball after the collision is 5.8 m/s

Explanation:

In absence of external forces on the system, we can apply the principle of conservation of momentum. The total momentum of the system must be conserved before and after the collision, so we can write:

$p_i = p_f\\m_1 u_1 + m_2 u_2 = m_1 v_1 + m_2 v_2$

where:

$m_1 = 1.0 kg$ is the mass of the pool ball

$u_1 = 10 m/s$ is the initial velocity of the pool ball

$v_1 = 3.0 m/s$ is the final velocity of the pool ball

$m_2 = 1.2 kg$ is the mass of the red ball

$u_2 = 0$ is the initial velocity of the red ball

$v_2$ is the final velocity of the red ball

Solving the equation for v2, we find the final velocity of the red ball after the collision:

$v_2 = \frac{m_1 u_1-m_1v_1}{m_2}=\frac{(1.0)(10)-(1.0)(3.0)}{1.2}=5.8 m/s$

Learn more about collisions:

brainly.com/question/13966693#

brainly.com/question/6439920

#LearnwithBrainly

7 0

3 years ago

As a car accelerates its tires increase their angular velocity from 114 rad/s to 131 rad/s in 0.43 seconds. What is the angular

e-lub [12.9K]

I think it's 39.53

(please do calculate it. I am not completely sure)

5 0

3 years ago

Read 2 more answers

1. To get to school, a girl walks 1 km North in 15 minutes. She

yulyashka [42]

Answer:

Average velocity of the girl is 1.25 m/s.

Explanation:

3 0

3 years ago