Test question for my account

Rewrite the following nested if-else statement as a switch statement that accomplishes exactly the same thing. Assume that num i

seropon [69]

Answer:

Answer explained below

Explanation:

The following is the nested if-else statement:

% if-based statement

if num < -2 || num > 4

f1(num)

else

if num <=2

if num >= 0

f2(num)

else

f3(num)

end

else

f4(num)

end

NOTE: the num is an integer variable that has been initialized and that there are functions f1, f2, f3 and f4.

The nested if-else statement can be replaced by switch statement as shown below:

switch num

case(0, 1, 2)

f2(num)

case(-2, -1)

f3(num)

case(3, 4)

f4(num)

otherwise

f1(num)

In this case, the switch based code is easier to write and understand because the cases are single valued or a few discrete values (not ranges of values)

8 0

3 years ago

2. Describe the kinds of pressures that might lead to unethical behavior.

slavikrds [6]

Answer:

Negative peer pressure and High-pressure expectations might be your answer.

Hope this helps :)

6 0

3 years ago

Consider a 8-m-long, 8-m-wide, and 2-m-high aboveground swimming pool that is filled with water to the rim. (a) Determine the hy

Stolb23 [73]

Answer:

The hydrostatic force of 313920 N is acted on each wall of the swimming pool and this force is acted at 1 m from the ground. The hydrostatic force is quadruple if the height of the walls is doubled.

Explanation:

To calculate force on the walls of swimming pool whose dimensions are given as 8-m-long, 8-m-wide, and 2-m-high. We know that formula for hydrostatic force is $\text {hydrostatic force}=\text {pressure} \times \text {area,}=\rho g h \times(l \times h)$

$\equiv \rho g h^{2} l$ , we know ρ=density of fluid=1000 $g / c m^{3}$ ,

g=acceleration due to gravity=9.81 $m / s^{2}$ , h=height of the pool=2 m and l=length of the pool=8 m.

hydrostatic force on each wall= $1000 \times 9.81 \times 2^{2} \times 8$ = 313920 N.

The distance at which hydrostatic force is acted is half of the height of the swimming pool.

At 1 m from the ground this hydrostatic force is acted on each wall.

The force is quadruple if the height of the walls of the pool is doubled this is because, the height is doubled and taken as h=4 m and substitute in the equation = $\rho g h^{2} l$ = $1000 \times 9.81 \times 4^{2} \times 8$ = 1255680 N. This is 4 times 313920 N.

5 0

3 years ago

In this lab, your task is to configure the external vEthernet network adapter with the following IPv6 address: Prefix: 2620:14F0

OverLord2011 [107]

Here is the complete question

You work as the IT administrator for a small corporate network. You need to create a separate subnet to use for testing. The test subnet needs access to the rest of the network through a router, but it should not have any local access to production machines.

You have installed Windows Server 2016 on CorpRTR, which you plan to use to isolate the test segment from the rest of the network. You'll use traditional routing or NAT.

In this lab, your task is to add the necessary role and role services to meet the stated requirements. Do not add unnecessary role services.

Answer & Explanation:

Complete this lab as follows:

1.In the notification area, right-click the Network icon and select Open Network and Sharing Center.

2.On the left, select Change adapter settings.

3.Right-click the vEthernet (External)adapter and select Properties.

4.Select Internet Protocol Version 6 (TCP/IPv6).

5.Select Properties.

6.Select Use the following IPv6 address.

7.In the IPv6 address field, enter 2620:14F0:45EA:0001:192:168:0:10as the IPv6 address.

8.In the Subnet prefix length field, enter 64.

9.Click OK.

10.Click Close.

11.In the Search the web and Windows field, enter cmd.

12.Under Best match, right-click Command Prompt and select Run as Administrator.

13.At the command prompt, type ipconfig /all and press Enter to view the IPv6 address.

4 0

4 years ago

The design for a new cementless hip implant is to be studied using an instrumented implant and a fixed simulated femur.

OlgaM077 [116]

Answer:

a) the velocity of the implant immediately after impact is 20 m/s

b) the average resistance of the implant is 40000 N

Explanation:

a) The impulse momentum is:

mv1 + ∑Imp(1---->2) = mv2

According the exercise:

v1=0

∑Imp(1---->2) = F(t2-t1)

m=0.2 kg

Replacing:

$0+F(t_{2} -t_{1} )=0.2v_{2}$

if F=2 kN and t2-t1=2x10^-3 s. Replacing

$0+2x10^{-3} (2x10^{-3} )=0.2v_{2} \\v_{2} =\frac{4}{0.2} =20m/s$

b) Work and energy in the system is:

T2 - U(2----->3) = T3

where T2 and T3 are the kinetic energy and U(2----->3) is the work.

$T_{2} =\frac{1}{2} mv_{2}^{2} \\T_{3} =0\\U_{2---3} =-F_{res} x$

Replacing:

$\frac{1}{2} *0.2*20^{2} -F_{res} *0.001=0\\F_{res} =40000N$

3 0

3 years ago