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Anvisha [2.4K]
3 years ago
10

A strong person and a weak person are trying to carry a ladder.How should they carry it in such a way that the weak person feels

less weight of the ladder?
plz its urgent .​

Physics
2 answers:
egoroff_w [7]3 years ago
8 0

Answer:

The stronger person holds it closer to them.

Explanation:

if the stronger person were to hold the ladder closer to them, they would be holding more of the weight thus making the weaker person have less weight. this is because of the center of gravity being closer to the stronger person.

zlopas [31]3 years ago
4 0

Answer:

Strong person should hold the ladder near the center while weak person should hold it at the end

Explanation:

So here we can see from the figure that in order to hold the ladder straight the two forces must counter balance the weight of the ladder

So here we know that

mg = F_1 + F_2

also for torque balance of the ladder we know that

F_1 r_1 = F_2 r_2

here we know that the distance of force F1 is less than that of other force F2 so

\frac{r_1}{r_2} < 1

so we can say that

\frac{F_2}{F_1} < 1

so weak person will apply less force if he hold it at the long distance

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A cheetah can run at a maximum speed 103 km/h and a gazelle can run at a maximum speed of 76.5 km/h. If both animals are running
Katena32 [7]

Answer:

1

 t_a  =  13.49 \  s

2

 The distance is   D = 55.2 \  m    

Explanation:

From the question we are told that

   The maximum speed of the cheetah is  v =  103 \  km/h =  28.61 \  m/s

    The maximum of  gazelle is  u =  76.5 \  km/h =  21.25 \  m/s

     The distance ahead is d =  99.3 \  m

Let  t_a denote the time which the cheetah catches the gazelle

Gnerally the equation representing the distance the cheetah needs to move in order to catch the gazelle is

           v* t_a = d +  u* t_a

=>          28.61 t_a = 99.3 +  21.25t_a

=>          7.36 t_a = 99.3

=>         t_a  =  13.49 \  s

Now at t =  7.5 s  

             7.5 v = D+  7.5u

=>          28.61 * 7.5  = D +  21.25* 7.5

=>          7.36 *  7.5 =D

=>         D = 55.2 \  m        

Hence the for the gazelle to escape the cheetah it must be 55.2 m

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A boat radioed a distress call to a Coast Guard station. At the time of the call, a vector A from the station to the boat had a
VashaNatasha [74]

Answer:

d = 39.7 km

Explanation:

initial position of the boat is 45 km away at an angle of 15 degree East of North

so we will have

r_1 = 45 sin15 \hat i + 45 cos15 \hat j

r_1 = 11.64 \hat i + 43.46\hat j

after some time the final position of the boat is found at 30 km at 15 Degree North of East

so we have

r_2 = 30 cos15\hat i + 30 sin15 \hat j

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now the displacement of the boat is given as

d = r_2 - r_1

d = (28.98\hat i + 7.76 \hat j) - (11.64 \hat i + 43.46\hat j)

d = 17.34 \hat i - 35.7 \hat j

so the magnitude is given as

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d = 39.7 km

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