By how much should a pair of light rays from a common source differ in distance traveled to produce destructive interference?

1 answer:

4 0

When you are equally distant from the speakers, their tones interfere constructively. ... <span>By how much should a pair of light rays from a common source differ in distance traveled to produce destructive interference</span>

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An engine manufacturer makes the claim that the engine they have developed will, on each cycle, take 100J of heat out of boiling

Alborosie

Answer:

Explanation:

Intake heat, QH = 100 J

output heat, Qc = 20 J

Work, W = 80 J

TH = 100°C = 373 K

Tc = 10°C = 283 K

TH/ Tc = 373 / 283 = 1.318

QH/Qc = 100 / 20 = 5

for a heat engine, those ratios should be same. so temperature is not correct.

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4 years ago

When you stretch a spring 13 cm past its natural length, it exerts a force of 21

zloy xaker [14]

Answer:

A. 1.6 N/cm

Explanation:

spring constant = 21/13 = 1.6 N/cm

8 0

3 years ago

The absolute pressure in water at a depth of 5m is read to be 145 kPa. Determine (a) the local atmospheric pressure, and (b) the

irga5000 [103]

Answer:

a) 95950 pascals

b) 137642.5 pascals

Explanation:

The absolute pressure (Pabs) on a fluid is:

$P_{abs}=P_{gauge}+P_{atm}$ (1)

With Pgauge the pressure due depth on the fluid and Patm the atmospheric pressure. Pgauge is equal to:

$P_{gauge}=\rho gh$ (2)

with ρ the fluid density, g the gravitational acceleration and h the depth on the fluid. Using (2) on (1) and solving for Patm:

$P_{atm}=P_{abs}-P_{gauge}=P_{abs}-\rho_{water} gh$

$P_{atm}=(145000Pa)-(1000\frac{kg}{m^{3}})(9.81\frac{m}{s^{2}})(5m)$

$P_{atm}=95950Pa$

b) Here we're going to use again (1) but now we have another value of density because it's other liquid, to know that value we should use the fact that specific gravity (S.G) for liquids is the ratio between fluid density and water density:

$S.G=\frac{\rho_{fluid}}{\rho_{water}}$