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4 years ago

By how much should a pair of light rays from a common source differ in distance traveled to produce destructive interference?

1 answer:

4 0

When you are equally distant from the speakers, their tones interfere constructively. ... <span>By how much should a pair of light rays from a common source differ in distance traveled to produce destructive interference</span>

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A box rests on a horizontal, frictionless surface. a girl pushes on the box with a force of 17 n to the right and a boy pushes o

Komok [63]

Refer to the diagram shown below.

The net force acting on the box is 17 - 13 = 4 N to the right.
The box moves on a friction surface by 3.5 m to the right.

By definition,
Work = Force x Distance.

(a) The work done by the girl is
W₁ = (17 N)*(3.5 m) = 59.5 J

(b) The work done by the boy is
W₂ = (13 N)*(-3.5 m) = - 45.5 J

(c) The work done by the net force is
W₃ = (4 N)*(3.5 m) = 14 J

Note that W₃ = W₁ + W₂

Answers:
(a) 59.5 J
(b) - 45.5 J
(c) 14 J

5 0

4 years ago

The Doppler effect using ultrasonic waves of frequency 2.25 × 106 Hz is used to monitor the heartbeat of a fetus. A (maximum) be

miss Akunina [59]

Answer:

$v = 2.88 \times 10^7 m/s$

Explanation:

As per Doppler's effect we know that the frequency of the sound that is observed by the detector is the reflected sound

This reflected sound is given as

$f' = f (\frac{v - v_h}{v + v_h})$

$f' = 2.25\times 10^6(\frac{v - 1540}{v + 1540})$

so we know that the beat frequency is

$\Delta f = 240 Hz$

so we will have

$f - f' = \Delta f$

$2.25 \times 10^6 - 2.25\times 10^6(\frac{v - 1540}{v + 1540}) = 240$

$1 - (\frac{v - 1540}{v + 1540}) = 1.07 \times 10^{-4}$

so we have

$0.99989 = (\frac{v - 1540}{v + 1540})$

$1.99989\times 1540 = 1.067 \times 10^{-4} v$

$v = 2.88 \times 10^7 m/s$

4 0

4 years ago

Ano-ano ang mga kultural na pamayanan na matatagpuan sa Luzon?<br>Help. Po hirap po ako dito

Nitella [24]

Answer:

Kultural na Pamayanan sa Luzon

*Ifugao

*Kalinga

*Gaddang

Explanation:

Sana makatulong po sa inyu...

I tried to answered it...

Pero your welcome in advance..

(◍•ᴗ•◍)

3 0

3 years ago

Read 2 more answers

When making a budget, you should prioritize ___________ before "__________." A. Needs/wants B. Wants/needs C. Electricity/Water

cestrela7 [59]

Answer:

Needs, Wants

Explanation:

Needs are necessary, wants are not

7 0

4 years ago

A rock is dropped from a 110-m-high cliff. How long does it take to fall (a) the first 55.0 m and (b) the second 55.0 m?

Genrish500 [490]

Answer:

a) t = 3.35[s]; b) t = 1.386[s]

Explanation:

We can solve this problem by dividing it into two parts, for the first 55 [m] and then the second part with the remaining 55 [m].

We will take the initial velocity as zero, as the problem does not mention that the Rock was thrown at initial velocity.

And using kinematics equations:

$v_{f}^{2}= v_{o}^{2}+2*g*y\\where:\\v_{o}=0\\g=gravity = 9.81[m/s^2]\\y=55 [m]\\v_{f}^{2}=0+2*9.81*55\\v_{f}=\sqrt{2*9.81*55} \\v_{f}=32.85[m/s]$

Now we can calculate the time:

$v_{f}=v_{o}+g*t\\t=\frac{v_{f}-v_{o}}{g}\\ t=\frac{32.85-0}{9.81}\\ t=3.35[s]$

Now we can calculate the second time, but using as a initial velocity 32.85[m/s].

The final velocity will be:

$v_{f}^{2}= v_{o}^{2}+2*g*y\\v_{f}=\sqrt{v_{o}^{2}+2*g*y} \\v_{f}=\sqrt{32.85^{2}+2*9.81*55 } \\v_{f}=46.45[m/s]$

Now we can calculate the second time:

$t=\frac{46.45-32.85}{9.81} \\t= 1.386[s]$

Note: The reason the second time is shorter even though it is the same distance is that the acceleration of gravity increases the speed of the rock more and more as it falls.

7 0

3 years ago