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3 years ago

6^5/2^3= what is the answer please

Physics

2 answers:

enot [183]3 years ago

7 0

Answer:

972

Explanation:

$\tt \cfrac{6^5}{2^3}= \cfrac{(2\cdot3)^5}{2^3}=\cfrac{2^5\cdot3^5}{2^3}=2^2\cdot3^5=4\cdot243=972$

kogti [31]3 years ago

6 0

Answer:

972

Explanation:

6^5/2^3

=7776/8

=972

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Answer:

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Explanation:

The formula for the orbital period of the moon is given by

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As the time period is inversely proportional to the square root of the acceleration due to gravity of the planet.

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3 years ago

A solenoid 91.0 cm long has a radius of 1.50 cm and a winding of 1300 turns; it carries a current of 3.60 A. Calculate the magni

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The magnitude of the magnetic field inside the solenoid is $6.46 \times 10^{-3} \ T$ .

The given parameters;

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radius of the solenoid, r = 1.5 cm = 0.015 m
number of turns of the solenoid, N = 1300
current in the solenoid, I = 3.6 A

The magnitude of the magnetic field inside the solenoid is calculated as;

$B = \mu_0 nI\\\\B = \mu_o(\frac{ N}{L} )I\\\\$

where;

$\mu_o$ is the permeability of frees space = 4π x 10⁻⁷ T.m/A

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Thus, the magnitude of the magnetic field inside the solenoid is $6.46 \times 10^{-3} \ T$ .

Learn more here:brainly.com/question/17137684

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3 years ago

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Answer:

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