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Sloan [31]
3 years ago
11

6^5/2^3= what is the answer please​

Physics
2 answers:
enot [183]3 years ago
7 0

Answer:

972

Explanation:

\tt \cfrac{6^5}{2^3}= \cfrac{(2\cdot3)^5}{2^3}=\cfrac{2^5\cdot3^5}{2^3}=2^2\cdot3^5=4\cdot243=972

kogti [31]3 years ago
6 0

Answer:

972

Explanation:

6^5/2^3

=7776/8

=972

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Match the following words with their definitions.
Brrunno [24]

Answer:

1. Doppler Effect = The apparent change in frequency perceived when the source of sound is approaching or moving away from an observer

2. Beats = The vibration of an object at its natural frequency, caused by a force or wave of the same frequency

3. Resonance = a series of alternating reinforcements and cancellations produced by the interference of waves

4. Shockwave = The cone-shaped wave made by a particle moving faster than the speed of a wave in that medium

Explanation:

I hope this helps. :)

7 0
4 years ago
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Explain objects in space motion. How do they move? What affects their motion?
Verizon [17]
Objects in space follow the laws or rules of physics, just like objects on Earth do. Things in space have inertia. That is, they travel in a straight line unless there is a force that makes them stop or change. The movement of things in space is influenced by gravity.
5 0
4 years ago
What type force is your answer in number 4
Alexandra [31]
  • When an object is stationary all the forces acting on the object comes in equilibrium with each other.

  • The forces acting on a stationary object are:
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  2. Gravitational force (downwards)
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3 0
3 years ago
outward from a wall just above floor level. A 1.5 kg box sliding across a frictionless floor hits the end of the spring and comp
sweet [91]

Answer:

v = 0.489 m/s

Explanation:

It is given that,

Mass of a box, m = 1.5 kg

The compression in the spring, x = 6.5 cm = 0.065 m

Let the spring constant of the spring is 85 N/m

We need to find the velocity of the box (v) when it hit the spring. It is based on the conservation of energy. The kinetic energy of spring before collision is equal to the spring energy after compression i.e.

\dfrac{1}{2}mv^2=\dfrac{1}{2}kx^2

v=\sqrt{\dfrac{kx^2}{m}} \\\\v=\sqrt{\dfrac{85\times (0.065)^2}{1.5}} \\\\v=0.489\ m/s

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4 years ago
In a simulation on earth, an astronaut in his space suit climbs up a vertical ladder. On the moon, the same astronaut makes the
mr Goodwill [35]

Answer:

Gravitational potential energy of the astronaut will change by a greater amount on the earth

Explanation:

Gravitational potential energy is expressed by the formula;

GPE = mgh

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Now, from constant values, gravity of moon is 1.62 m/s² while gravity of the earth is 9.81 m/s².

This means that if we plug in the values of g on the earth and g on the moon, the potential energy on the earth would be greater than that of the moon

Thus, gravitational potential energy of the astronaut will change by a greater amount on the earth

8 0
3 years ago
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