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salantis [7]
3 years ago
7

Write the chemical formula of tetraphosphours octasulfide

Chemistry
1 answer:
ArbitrLikvidat [17]3 years ago
8 0

Answer:

P4 S8

Explanation:

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If a 50.0 mL sample of gas exerts a pressure of 0.59 atm at 35.0 Celsius. What volume will the gas occupy at STP?
Rudik [331]

Explanation:

P1V1/T1 =P2V2/T2

V2 =P1V1T2/P2T1

0.59×0.05×273/1×308

V2 =0.03L

8 0
3 years ago
2KI + Pb(NO3)2 → 2KNO3 + PbI2 Determine how many moles of KNO3 are created if 0.03 moles of KI are completely consumed.
ElenaW [278]
2:2 so the same proportion 
0,03

6 0
3 years ago
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How to calculate the gravimetric factor
lianna [129]
The only thing you need  to know in order to calculate <span>the gravimetric factor is the formula :
</span>Grav. Factor = m x FW (substance sought) /n x FW (Substance Weight)
I am pretty sure that you will find it helpful! Regards.
3 0
3 years ago
How many o atoms are present in 1.04 mol of mgso4??
HACTEHA [7]
To figure this out, you need to figure out how many molecules of mgso4 you have.
If you have 1.04 moles of MgSO4, you have that many moles times avogadro's number (6.022*10^23 molecules/mole).
1.04 moles MgSO4 * (6.022*10^23 molecules MgSO4)/1 mole MgSO4 =
6.263 *10^23 molecules MgSO4
Next, there are 4 oxygen atoms per molecule of MgSO4, so we multiply the number of molecules of MgSO4 by 4 to get the number of oxygen atoms.
6.263 *10^23 molecules MgSO4 * (4 oxygen atoms/1 MgSO4 molecule) = 2.51 * 10^24 oxygen atoms in 1.04 moles of MgSO4
3 0
4 years ago
A chemist needs 500.0 mL of a 1.500 M perchloric acid solution. The stockroom provides the chemist with
Lynna [10]

Answer:-  47.62 mL

Solution:- It is a dilution problem where we are asked to calculate the volume of 15.75 M perchloric acid solution required to make 500.0 mL of 1.500 M solution.

For solving this type of problems we use the dilution equation:

M_1V_1=M_2V_2

Where, M_1 is the concentration of the concentrated solution and V_1 is it's volume.

M_2 is the concentration of the diluted solution and V_2 is it's volume.  Let's plug in the values in the equation and solve it for V_1 .

15.75M(V_1)=1.500M(500.0mL)

On rearranging this for V_1 :

V_1=\frac{1.500M(500.0mL)}{15.75M}

V_1=47.60mL

So, 47.62 mL of 15.75 M perchloric acid are required to make 500.0mL of 1.500 M solution.

3 0
4 years ago
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