Answer:
A3+ and B-
Explanation:
Elements in group 13 have outermost electron configuration, ns2np1 hence they form trivalent positive ions.
Elements in group 17 have outermost electron configuration ns2np5 hence they form univalent negative ions.
This implies that, if element A is in Group 13 and element B is in Group 17, the ions formed are A3+ and B-.
Moles of Hydrogen present: 100 / 2 = 50 moles
Moles of Nitrogen present: 200 / 28 = 7.14 moles
Hydrogen required by given amount of nitrogen = 7.14 x 3 = 21.42 moles
Hydrogen is excess so we will calculate the Ammonia produced using Nitrogen.
Molar ratio of Nitrogen : Ammonia = 1 : 2
Moles of ammonia = 7.14 x 2 = 14.28 moles
Answer:
the answer is 11
Explanation:
Ok, let us understand what is an atomic number, an atomic number is simply the proton number, the atomic number is always seen at the bottom left corner in a element of a periodic table, it is the number of proton in a atom of a certain element.
The most electronegative element will have atoms with strongest association for electrons. Electronegativity is the ability of an atom to attract electrons and form bonds with electrons. . In the periodic table the left hand side favors the loss of electrons because less energy is required to lose an electron than to gain an electron. On the other han, the right hand side favors gaining electrons since less energy is required than when losing electrons.
Henceforth, from left to right in the periodic table the tendency to gain electrons increases. In contrast, going down a group there is decreased association for electrons, because atomic radius increases which suggests that valence electrons are further away from the nucleus.This makes fluoride the ion with strongest association of electrons. The noble gases have a complete shell so cannot attract electrons to themselves, which means they have no electronegativity.