Question

Glucose is an important sugar in many biochemical reactions what is the molarity of a solution that contains 500 grams of glucose (molecular weight= 180.16 g/mol) in 7.02 liters of solution
a. .56M
b. .78 M
c. 3.85 M
b. 4.98 M

Answer 1

Number of moles :

500 / 180.16 => 2.775 moles

Volume = 0.72 L

M = n / V

M = 2.775 / 0.72

M = 3.85 M

hope this helps!

Answer 2

Answer:

The correct answer is c.

Explanation:

First, look for the same problem to verify that the correct volume is 0.702 L.

Now we must calculate the amount of glucose moles (n) in the 500g:

n = $\frac{500 g}{180 \frac{g}{mol} }$

n = 2,7 mol

Molarity is given by moles of compound per liter. In this way, we calculate the molarity (M) as:

M = $\frac{2,7 mol}{0,702 L}$

M = $3,85\frac{mol}{L}$

Have a nice day!