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Kruka [31]
3 years ago
12

Please help on this one?

Physics
2 answers:
mario62 [17]3 years ago
8 0
The answer would be D:)
Novay_Z [31]3 years ago
7 0

D. That the storm is moving toward Hillville and that residents be prepared.

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How much energy, in Joules, is needed to raise the temperature from 25.87°C to 33.16°C in a 2.66 kg block of each of the followi
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Answer:

(a) Silver, H = 455.67 J

(b) Iron, H = 870.67 J

(c) titanium, H = 1012.23 J

Explanation:

mass of block, m = 2.66 kg = 266 g

T1 = 25.87° C

T2 = 33.16° C

ΔT = T2 - T1 = 33.16 - 25.87 = 7.29° C

(a) Specific heat of silver, c = 0.235 J/g K

The heat required is given by

H = m x c x ΔT

H = 266 x 0.235 x 7.29 = 455.67 J

(b) Specific heat of iron, c = 0.449 J/g K

The heat required is given by

H = m x c x ΔT

H = 266 x 0.449 x 7.29 = 870.67 J

(c) Specific heat of titanium, c = 0.522 J/g K

The heat required is given by

H = m x c x ΔT

H = 266 x 0.522 x 7.29 = 1012.23 J

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3 years ago
Second and third class levers are differentiated by __________.
ira [324]

Answer:

i think it is b

hope this helps

Explanation:

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3 years ago
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Which of the following statements about globular clusters is true? All stars in the cluster have approximately the same mass. Al
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Most stars in the cluster are yellow or reddish in color. Most

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2 years ago
In a racquetball game, your opponent repeatedly hits the same type of serve off the front wall and it lands in approximately the
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b

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2 years ago
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a projectile is shot horizontally from the edge of a cliff, 230m above the ground. the projectile lands 300m from base of the cl
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Answer:

The time taken by the projectile to hit the ground is 6.85 sec.

Explanation:

Given that,

Vertical height of cliff = 230 m

Distance = 300 m

Suppose, determine the time taken by the projectile to hit the ground.

We need to calculate the time

Using second equation of motion

s=ut+\dfrac{1}{2}gt^2

Where, s = vertical height of cliff

u = initial vertical velocity

g = acceleration due to gravity

Put the value in the equation

230=0+\dfrac{1}{2}\times9.8\times t^2

t=\sqrt{\dfrac{230\times2}{9.8}}

t=6.85 sec

Hence, The time taken by the projectile to hit the ground is 6.85 sec.

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3 years ago
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