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lesya [120]
3 years ago
7

Given that ka for hclo is 4.0 x 10-8 at 25 °c, what is the value of kb for clo- at 25 c

Chemistry
1 answer:
OLga [1]3 years ago
7 0
The Ka of HClO is 4.0 x 10^-8 at 25 C. The dissociation of HClO is:

HClO + H2O ---> H+ + ClO -    T = 25 C

Ka = 4.0 x 10^-8 = [H+][ClO-]/[HClO]

pH = -log[4.0 x 10^-8]
pH = 7.40
pOH = 14 - 7.40
         = 6.60
Kb = 10^-6.6

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victus00 [196]

Answer:

okay but give me brainliest

Explanation:

A volcano is formed when hot molten rock, ash and gases escape from an opening in the Earth's surface. The molten rock and ash solidify as they cool, forming the distinctive volcano shape shown here. As a volcano erupts, it spills lava that flows downslope. Volcanic flows are called lahars.

7 0
3 years ago
Avogadro's law states that the _____ of a gas is directly proportional to the _____ of the gas when _____ stay the same
attashe74 [19]

Answer:

The three blanks for this answer, are

1. volumen

2. moles

3. Temperature and pressure.

So, Avogadro's law states that the volume of a gas is directly proportional to the moles of the gas when temperature and pressure stay the same

Explanation:

Imagine you have 10 moles of a gas which is contained in 50 L. How many moles of that gas, you will have if the volumen has been reduced to 10 L. (Of course, don't forget that T° and pressure are the same)

There is an equation like this, initial moles /initial volume = moles at the end/volume at the end, (Avogadro law for gases), so 10/50 =moles at the end/10.  When u operate, moles at the end = (10 x 10) / 50.

Moles at the end are 2. Did u get it?. Volumen has been reduced, also the moles.

7 0
4 years ago
GivenL C2H2 + 5O2 ------> 4 CO2 + 2H2O
diamong [38]

Answer:

101 L

Explanation:

35.0 g KOH ÷ 56.09 g/mol KOH × (1 mol H2O/ 1 mol KOH) × 18 g/mol H2O = 11.2 g H2O

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35.0 g KOH is the limiting reactant

7 0
3 years ago
A horizontal pipe 15 cm in diameter and 4 m long is buried in the earth at a depth of 20 cm. The pipe-wall temperature is 75 deg
Basile [38]

Explanation:

The given data for case (1) is as follows.

  h = 20 cm = 0.2 m

Assuming that a rectangular slab is placed above the pipe and we will calculate the heat transfer as follows.

              Q = kA \frac{\Delta T}{L}

  where,    A = area

                  L = length

                  k = thermal conductivity = 0.8 W/m

             \Delta T = change in temperature.

Therefore, putting the given values into the above formula as follows.

            Q = kA \frac{\Delta T}{L}

                = 0.8 W/m \times (4 m \times 0.15 m) \frac{75 - 5}{0.2}

                = 168 W

For case (2), h = 180 cm = 1.8 m

Therefore, heat lost will be calculated as follows.

                       Q = kA \frac{\Delta T}{L}

                           = 0.8 W/m \times (4 m \times 0.15 m) \frac{75 - 5}{1.8}

                           = 18.67 W

Thus, we can conclude that 18.67 W heat lost if the pipe was buried at a depth of 180 cm.

8 0
3 years ago
Will give brainliest, like, 5 stars and 5 points to best answer
Oliga [24]

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6 0
3 years ago
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