Solids are the only ones that keep their shape and volume no matter the container.
Answer:
The standard potential for this galvanic cell is 1.25 V
Explanation:
Step 1
Oxidation: Fe(s) → Fe^2+ (aq) + 2e- E° = 0.447 V
Reduction: Ag+(aq) + e- → Ag(s) E° = 0.7996 V
The electron number for the oxidation is 2; the electron number for the reduction is 1.
By multiplying the reduction reaction by 2, we make the electron number the same between the two half-equations
2
Ag+(aq) + 2e- → 2Ag(s) E° = 0.7996 V
Step 2: The overall balanced equation
Fe(s) + 2Ag+(aq) → Fe^2+(aq) + 2ag(s) E° = 0.447 V + 0.7996 V = 1.25V
The standard potential for this galvanic cell is 1.25 V
Atoms of one element are converted to atoms of another element through transmutation or nuclear transmutation.
Answer:
11.25 moles of O₂.
Explanation:
We'll begin by writing the balanced equation for the reaction. This is illustrated below:
C₃H₈ + 5O₂ —> 3CO₂ + 4H₂O
From the balanced equation above,
1 mole of C₃H₈ reacted with 5 moles of O₂.
Finally, we shall determine the number of mole of O₂ needed to react with 2.25 moles of C₃H₈. This can be obtained as follow:
From the balanced equation above,
1 mole of C₃H₈ reacted with 5 moles of O₂.
Therefore, 2.25 moles of C₃H₈ will react with = 2.25 × 5 = 11.25 moles of O₂.
Thus, 11.25 moles of O₂ is needed for the reaction.
C₂HO₂Br₃
Explanation:
Given parameters:
Carbon = 8.09%
Hydrogen = 0.34%
Oxygen = 10.78%
Bromine = 80.78%
Unknown:
Empirical formula = ?
Solution:
The empirical formula is the simplest formula of a compound.
To find it, we use the process below:
C H O Br
Percent
compo-
sition 8.09 0.34 10.78 80.78
Molar
mass 12 1 16 80
Numb-
of moles 8.09/12 0.34/1 10.78/16 80.78/80
0.68 0.34 0.68 1
Divide
by
smallest 0.68/0.34 0.34/0.34 0.68/0.34 1/0.34
2 1 2 3
Empirical formula C₂HO₂Br₃
learn more:
Empirical formula brainly.com/question/2790794
#learnwithBrainly