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3 years ago

H2O(s) is classified as

Chemistry

2 answers:

Inga [223]3 years ago

8 0

H2O is classified as water.

Hope this helps! God bless
-vf

Salsk061 [2.6K]3 years ago

7 0

H2O Classified as a Molecular Compound composed of 2 or more Non-Metals, or water

(H = Hydrogen),(O = Oxygen) = Non - Metals

Liquid or Gas Form(water vapor/steam); also, has 2 Atoms of hydrogen. That's why it has(2 after the H, and one oxygen atom.).

Hope that helps!!!

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3 years ago

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Animals breathe oxygen and release carbon dioxide during cellular respiration according to the equation below. How much oxygen i

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Answer:

14.544 g of oxygen is needed to produce 120 grams of carbon dioxide.

Explanation:

Animals take in oxygen and breathe out carbon dioxide during cellular respiration. The reaction for the metabolism of the food in the animal body is:

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As can be seen from the reaction stoichiometry that:

6 moles of carbon dioxide gas can be produced from 1 mole of oxygen gas in the process of metabolism of glucose.

Also,

Given :

Mass of carbon dioxide gas = 120 g

Molar mass of carbon dioxide gas = 44 g/mol

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

Thus, moles of carbon dioxide are:

$moles_{CO_2} = \frac{120 g}{44 g/mol}$

$moles_{CO_2} = 2.7273 mol$

As mentioned:

6 moles of carbon dioxide gas can be produced from 1 mole of oxygen gas in the process of metabolism of glucose.

1 mole of carbon dioxide gas can be produced from 1/6 mole of oxygen gas in the process of metabolism of glucose.

2.7273 mole of carbon dioxide gas can be produced from $\frac{1}{6} \times 2.7273$ moles of oxygen gas in the process of metabolism of glucose.

Thus, moles of oxygen gas needed = 0.4545 moles

Molar mass of oxygen gas = 32 g/mol

The mass of oxygen gas can be find out by using mole formula as:

$moles = \frac{Mass\ taken}{Molar\ mass}$

Thus,

$Mass\ of\ oxygen\ gas = Moles \times Molar mass}$

$Mass\ of\ oxygen\ gas = 0.4545 \times 32}$

$Mass\ of\ oxygen\ gas = 14.544 g$

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2 years ago

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3 years ago

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How many moles of oxygen are needed to react with 87 grams of aluminum

labwork [276]

Answer:

2.4 moles of oxygen are needed to react with 87 g of aluminium.

Explanation:

Chemical equation:

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Mass of aluminium = 87 g

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2 years ago