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3 years ago

H2O(s) is classified as

Chemistry

2 answers:

Inga [223]3 years ago

8 0

H2O is classified as water.

Hope this helps! God bless
-vf

Salsk061 [2.6K]3 years ago

7 0

H2O Classified as a Molecular Compound composed of 2 or more Non-Metals, or water

(H = Hydrogen),(O = Oxygen) = Non - Metals

Liquid or Gas Form(water vapor/steam); also, has 2 Atoms of hydrogen. That's why it has(2 after the H, and one oxygen atom.).

Hope that helps!!!

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Can a window pane be considered a mineral?

hichkok12 [17]

Answer:

Explanation:

The glass (which does not crystallize even though it is accepted) of a window is NOT a mineral, since it is neither a substance of natural origin (although it is manufactured from natural components) nor does it have a defined crystalline structure, that is, the atoms they are not arranged in an orderly and regular way along axes and planes forming flat faces that keep a symmetry.

Remember that a mineral is defined as a solid, inorganic, homogeneous substance, of natural origin, with a crystalline structure and a determined and well-defined chemical composition within narrow margins and that has regular and characteristic physical properties.

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3 years ago

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Identify which reaction is NOT a chemical reaction.<br> es )

vova2212 [387]

Answer:

You never listed the options

Explanation:

A chemical reaction is a process that involves rearrangement of the molecular or ionic structure of a substance, as opposed to a change in physical form or a nuclear reaction.

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3 years ago

An element with the general electron configuration for its outermost electrons of ns2np1 would be in which element group?

Firdavs [7]

Electron configuration is the electron distribution in the molecular and atomic orbital. An element with configuration ns²np¹ will be in the 3A group. Thus, option B is correct.

<h3>What is electronic configuration?</h3>

The electronic configuration has been the arrangement and distribution of the sub-atomic particle, an electron in the atomic shells.

The electronic configuration given is, ns²np¹. Here, there are three valence electrons in the outermost orbit. As it has been known that the number of the valence electron gives the number of the group.

Therefore, option B. 3A group or 13 group is the correct option.

Learn more about electronic configuration here:

brainly.com/question/11182760

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Your question is incomplete, but most probably your full question was, An element with the general electron configuration for its outermost electrons of ns2np1 would be in which group?

a. 2a

b. 3a

c. 4a

d. 5a

e. 8a

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2 years ago

PLEASE ANSWER FAST AND YOU WILL GET BRAINLIESTTTTTTT!!!!!!! And POINTSSSSSS!! PLEASE ANSWER FAST AND YOU WILL GET points and BRA

stiks02 [169]

Answer:

B on both questions

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3 years ago

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URGENT CHEMISTRY EXPERT!

vovangra [49]

Answer:

Part 1: 7.42 mL; Part 2: 3Cu²⁺(aq) + 2PO₄³⁻(aq) ⟶ 2Cu₃(PO₄)₂(s)

Explanation:

Part 1. Volume of reactant

(a) Balanced chemical equation.

$\rm 2Na_{3}PO_{4} + 3CuCl_{2} \longrightarrow Cu_{3}(PO_{4})_{2} + 6NaCl$

(b) Moles of CuCl₂

$\text{Moles of CuCl}_{2} =\text{ 16.7 mL CuCl}_{2} \times \dfrac{\text{0.200 mmol CCl}_{2}}{\text{1 mL CuCl}_{2}} = \text{3.340 mmol CuCl}_{2}$

(c) Moles of Na₃PO₄

The molar ratio is 2 mmol Na₃PO₄:3 mmol CuCl₂

$\text{Moles of Na$_{3}$PO}_{4} = \text{3.340 mmol CuCl}_{2} \times \dfrac{\text{2 mmol Na$_{3}$PO}_{4}}{\text{3 mmol CuCl}_{2}} =\text{2.227 mmol Na$_{3}$PO}_{4}$

(d) Volume of Na₃PO₄

$V = \text{2.227 mmol Na$_{3}$PO}_{4}\times \dfrac{\text{1 mL Na$_{3}$PO}_{4}}{\text{0.300 mmol Na$_{3}$PO}_{4}} = \text{7.42 mL Na$_{3}$PO}_{4} \\\\\text{The reaction requires $\large \boxed{\textbf{7.42 mL Na$_{3}$PO}_{4}}$}$

Part 2. Net ionic equation

(a) Molecular equation

$\rm 2Na_{3}PO_{4}(\text{aq}) + 3CuCl_{2}(\text{aq}) \longrightarrow Cu_{3}(PO_{4})_{2}(\text{s}) + 6NaCl(\text{aq})$

(b) Ionic equation

You write molecular formulas for the solids, and you write the soluble ionic substances as ions.

According to the solubility rules, metal phosphates are insoluble.

6Na⁺(aq) + 2PO₄³⁻(aq) + 3Cu²⁺(aq) + 6Cl⁻(aq) ⟶ Cu₃(PO₄)₂(s) + 6Na⁺(aq) + 6Cl⁻(aq)

(c) Net ionic equation

To get the net ionic equation, you cancel the ions that appear on each side of the ionic equation.

The net ionic equation is

3Cu²⁺(aq) + 2PO₄³⁻(aq) ⟶ Cu₃(PO₄)₂(s)

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