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Kay [80]
3 years ago
10

Consider a charged particle at a pointS whose coordinates are (8 m, 4 m, 10 m). We would like to find the electric field vector

at a point P whose coordinates are (7 m, 2 m, 6 m). The "unit vector" r ^ is a vector that points from S to P that has length of 1 (or "unity"). What is its y component, in meters
Physics
1 answer:
gregori [183]3 years ago
8 0

Answer:

E=k*\frac{q}{21}*u

u=\frac{1}{\sqrt{21}} *(-1,-2,-4)m

u_{y}=\frac{-2}{\sqrt{21}} m

Explanation:

q: particle's charge

k: coulomb constant

E=E*u

r=r*u

r=distancia vectorial entre P y S

r=distancia escalar entre P y S

E: Electric field vector

E: magnitud of magnetic field vector

u: unit vector radial

then:

E=k*q/r^{2}

r=r*u

r=P-S=(-1,-2,-4)m

r^{2}=(Magnitude(P-S))^2=(-1)^2+(-2)^2+(-4)^2=21

r=\sqrt{21}

E=k*\frac{q}{21}*u

u=r/r=\frac{1}{\sqrt{21}} *(-1,-2,-4)m

u_{y}=\frac{-2}{\sqrt{21}} m

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