Question

What is the net ionic equation for the reaction that is represented by the following total ionic equation? 6Na+ + 2Ca^2+ + 6CI- → 6Na+ + 6CI- + Ca3(PO4)2

Answer 1

Answer:

$\boxed{\rm 3Ca^{2+} + 2PO_{4}^{3-} \longrightarrow Ca_{3}(PO_{4})_{2}}$

Explanation:

$\textbf{Ionic equation}\\\rm \textbf{6Na}^{+} + 3Ca^{2+} + \textbf{6Cl}^{-} + 2PO_{4}^{3-} \longrightarrow \textbf{6Na}^{+} + \textbf{6Cl}^{-} + Ca_{3}(PO_{4})_{2}$

Net ionic equation

Cancel all ions that appear on both sides of the reaction arrow (in boldface).

$\boxed{\rm 3Ca^{2+} + 2PO_{4}^{3-} \longrightarrow Ca_{3}(PO_{4})_{2}}$