Answer:
Approximately
, assuming that the rocket had no propulsion onboard, and that air resistance on the rocket is negligible.
Explanation:
Initial velocity of this rocket:
.
When the rocket is at its maximum height, the velocity of the rocket would be equal to
. That is:
.
The acceleration of the rocket (because of gravity) is constantly downwards, with a value of
.
Let
denote the distance that the rocket travelled from the launch site to the place where it attained maximum height. The following equation would relate
to
,
, and
:
.
Apply this equation to find the value of
:
.
In other words, the maximum height that this rocket attained would be
.
Again, assume that the air resistance on this rocket is negligible. The rocket would return to the ground along the same path, and would cover a total distance of
.
<h2>The acceleration of car is 0.2 ms⁻²</h2>
Explanation:
When the car moves , the distance covered is calculated by the relation
S = u t +
a t²
In this question u = 0 , because car was at rest initially
Thus S =
a t²
here S is displacement and a is the acceleration of car
Therefore 360 =
a ( 60 )²
Because time taken is one minute or 60 seconds
Therefore a = 
or a = 0.2 m s⁻²
Answer:
If there is a net force acting on an object, the object will have an acceleration and the object's velocity will change. ... Newton's second law states that for a particular force, the acceleration of an object is proportional to the net force and inversely proportional to the mass of the object.
Explanation: