Answer:
Explanation:
You need to know one piece of information for these problems. That is as follows:
There are 6.02 x 10^23 atoms in a mole of atoms or 6.02 x 10^23 molecules in a mole of molecules (actually there are 6.02 x 10^23 in a mole of anything).
So in 3.161 x 10^21 molecules of CO2 there are 3.161 molecules x (1 mole CO2/6.02 x 10^23 molecules CO2)= ?? moles CO2. Then multiply that by 2 to find the moles of O in CO2.
The others are done th same way.
Answer:
0.5m/s2
Explanation:
Data obtained from the question include:
u (initial velocity) = 0m/s
v (final velocity) = 30m/s
t (time) = 1min = 60secs
a (Acceleration) =?
a = v — u/t
a = 30—0 / 60
a = 30/60
a = 0.5m/s2
Answer:
(a) Iron is being oxidized.
(d) Sulfur is being reduced.
Explanation:
Let's consider the following redox reaction.
8 Fe(s) + S₈(s) → 8 FeS(s)
Iron is being oxidized according to the following oxidation half-reaction:
Fe(s) → Fe²⁺(s) + 2 e⁻
Sulfur is being reduced according to the following reduction half-reaction:
S₈(s) + 16 e⁻ → 8 S²⁻(s)
Answer:
the answer is 11.111 and when you round it to the nearest one it’s 11, but to the nearest tenth it’s 10
Explanation:
