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Dafna1 [17]
3 years ago
7

Which statement best describes the formation of a solution?

Chemistry
1 answer:
aev [14]3 years ago
6 0

Answer:

A small amount of solute dissolved in a larger amount of solvent.

Take this analogy to help you understand, if you were to put a teaspoon of sugar in a liter of water it would dissolve, but if you put a sack of sugar in it it would not dissolve! The solute is what is being dissolved and the solvent is what dissolves the solute, so that eliminates some of the options.

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What is the molarity of HCl if 34.81 mL of a solution of HCl contain 0.3297 g of HCl?
Temka [501]

Answer:

0.2598 M

Explanation:

Molarity is mol/L, so we have to convert the grams to moles and the mL to L. To convert between grams and moles you need the molar mass of the compound, which is 36.46g/mol.

0.3297gHCl*\frac{1molHCl}{36.46gHCL} = 0.00904279 mol HCl

34.81 mLHCl * \frac{1L}{1000L} = 0.03481 L HCl

\frac{0.00904279molHCl}{0.03481 L HCl} = 0.25977554 mol/L

Round to the lowest number of significant figures = 0.2598 M

6 0
3 years ago
Nitric acid (HNO3) is a strong acid, and it is titrated with a standard solution of sodium hydroxide (NaOH), a strong base. Whic
aev [14]
C. pH = 7.0

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4 0
3 years ago
Read 2 more answers
Elements in the same period of the periodic table exhibit similar physical and chemical properties.
Vladimir [108]

Answer:

same valency electrons

Explanation:

example g 1 elements

5 0
3 years ago
How many moles of neon occupy a volume of 14.3 l at stp? how many moles of neon occupy a volume of 14.3 l at stp? 1.57 moles 0.6
andriy [413]
The  number   of  neon  moles  that  occupy  a volume of 14.3 l  at STP is calculated as follows

At STP 1  mole = 22.4 liters

what about  14.3 liters

by cross  multiplication
= (1 mole x 14.3 l)/22.4 l =0.638  moles  of  neon


5 0
3 years ago
scandium47 has a half-life of 35s. suppose you have a 45g sample of scadium 47 how much of the sample remains unchanged after 14
Mars2501 [29]

 The much  of the sample that would remain  unchanged  after 140 seconds is 2.813 g

Explanation

Half life  is time taken for the quantity  to reduce  to half its original value.

if the half life  for Scandium  is 35 sec, then the number  of half life in 140 seconds

=140 sec/ 35 s = 4 half life

Therefore 45 g after first half life = 45 x1/2 =22.5 g

               22.5 g after second half life = 22.5 x 1/2 =11.25 g

            11.25 g after third half life = 11.25 x 1/2 = 5.625 g

             5.625 after  fourth half life = 5.625 x 1/2 = 2.813

therefore 2.813 g  of Scandium 47 remains  unchanged.

4 0
3 years ago
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