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zimovet [89]
3 years ago
6

Convert from scientific notation to standard form 9.512 x 10-8

Physics
1 answer:
eduard3 years ago
5 0
Standard form: 0.00000009512
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What is the velocity of a car if it travels east 340 meters in 10 seconds? V = d/t
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Answer:

The awnser is d

Explanation:

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Suppose high tide is at midnight, the water level at midnight is 3 m, and the water level at low tide is 0.5 m. Assuming the nex
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We have that the time, to the nearest minute, when the water level is at 1.125 m for the second time after midnight is

t=10.0hours

From the Question we are told that

Maximum height h_{max}=3m

Minimum height  H_{min}=0.5m

Time for  next high tide will occurT=12 hours =>720 min

Generally Average Height

h_{avg}=\frac{3+0.5}{2}\\\\h_{avg}=1.75

Therefore determine Amplitude to be

A=h_{max}=j_{avg}\\\\A=3-1.75\\\\A=1.25

Generally, the equation for Time is mathematically given by

At t=0

h(x)=Acos(Bx)+h_{avg}

Where

B=\frac{2\pi}{P}\\\\B=\frac{2\pi}{720}\\\\B=8.73*10^{-3}

Therefore

h(t)=Acos8.73*10^{-3}(t)+h_{avg}

Hence the Time at T=1.125 is

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3 years ago
From Gauss's law, the electric field set up by a uniform line of charge is given by the following expression where is a unit vec
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Answer:

\Delta V=\lambda *ln(r_{2}/r_{1}) /\ (2\pi*\epsilon_{o})

Explanation:

Using the Gauss Law, we obtain the electric Field for a uniform large line of charge:

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We calculate the potential difference from the electric field:

\Delta V=-\int\limits^{r_{1}}_{r_{2}} E \, dr =-\int\limits^{r_{1}}_{r_{2}} \lambda dr/ (2\pi*r*\epsilon_{o})=\lambda *ln(r_{2}/r_{1}) /\ (2\pi*\epsilon_{o})

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A cyclist has a constant speed of 12 m/s. What is the magnitude of the displacement of the cyclist after 18 seconds?
Katyanochek1 [597]

Answer:

216 m

Explanation:

Assuming a straight line:

Δx = vt

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