Answer:
The final solution is 1.5 times more acidic than the initial solution
Explanation:
1) The saturation point at 25°C is 35.7 g of NaCl / 100 g of water => 35.7 %
Under normal circumstances water will not accept more salt than that.
2) The solution with 1.55 mol of NaCl dissolved in 250 mL of water =>
molar mass of NaCl = 22.99 g/mol + 35.45 g/mol = 58.44 g/mol
grams of NaCl = 1.55 mol * (molar mass of NaCl) = 1.55mol * 58.44 g/mol = 90.58 grams of NaCl
grams of water = 250 mL * 1 g/mL = 250 g/g.
Concentration of the solution: [90.58 g NaCl / 250 g H2O] * 100 = 36.23 %
3) Conclusion: the solution has more salt than the saturation value. This means that the solution is supersaturated.
Supersaturation is a special condition, which is unstable, but that is not part of the questions.
The answer is supersaturated,
Answer:
1
Recall that at STP, 1 mole of any ideal gas occupies 22.4 liters. Volume O2 gas = 0.0510 moles O2 x 22.4 L/mole = 1.14 liters (3 sig.
Explanation:
hope this helps
Explanation:
<h3>Here, mass = 5kg </h3><h3> acceleration = 10m/s^2</h3>
<h3>according to the question ;</h3><h3>F = m×a ( from 2nd law of motion)</h3><h3>F = 5kg × 10m/s^2</h3><h3>F = 50kgm/s^2 or NEWTON </h3>
<h3>SO THE FORCE NEEDED IS 50 NEWTON</h3>
<h2>I HOPE THAT THIS ANSWER HELPS YOU </h2>
