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timurjin [86]
4 years ago
9

A scientist at a space research center is doing research on near-Earth objects and determining the kinetic energy of a theoretic

al object. A meteorite with a mass of 12 grams falls to Earth. If the meteorite’s velocity is 35 kilometers/second, what is its kinetic energy?
Physics
2 answers:
kvv77 [185]4 years ago
7 0
(Taking an online class with this exact question, Answer given by program)
KE= 1/2 mv^2
     = 1/2(0.012)(35,000)^2
     = 7.35x10^6
The kinetic energy of the meterorite is 7.35 x 10^6 Joules
Marysya12 [62]4 years ago
6 0
<span>its kinetic energy is 7350kJ 
</span>

Kinetic energy is given as = \frac{1}{2} mv^{2}

Now, m = 12 gms = 0.012 kg
 And, velocity = 35 kilometers/second = 35000 m/sec

Kinetic energy is given as = \frac{1}{2} 0.012 kg * 35000*35000 m/[tex] s^{2}
                        = 6 10^{-2}×1225 ×10^{6} m/s^{2} 
                        = 7350 kJ
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BlackZzzverrR [31]

Answer:

E = 8.5 * 10^6 V/m

Explanation:

In general we have the following relation between the Electric Field and the Elecric Potential:

\int\limits^2_1 {\vec{E} \cdot\vec{dl}} = V_{2} -V_{1}

Due to the vector nature of the electric filed, we can only know the mean Electric field E across the membrane, and take it out from the integral, that is:

E = (ΔV)/L

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Therefore:

E = 8.53933*10^6 V/m

rounding to the first tenth:

E = 8.5 * 10^6 V/m

3 0
3 years ago
What is an example of gravitational potential to kinetic to electrical current?
Alecsey [184]
Chemical to thermal to electrical current: Burning of coal or natural gases. Gravitational potential to kinetic to electrical current.
6 0
3 years ago
Earth attracts a person with a gravitational force of 7.0 × 102 newtons. What is the magnitude of the force with which the indiv
Anuta_ua [19.1K]
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Gravitational force always acts in pairs.
Whatever force the Earth attracts something with,
the thing attracts the Earth with exactly the same force.

If Earth attracts a person with a gravitational force of <span><span>7.0 × 10² </span>newtons,
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5 0
3 years ago
A particle with charge -40.0nC is on the x axis at the point with coordinate x=0 . A second particle, with charge -20.0 nC , is
ICE Princess25 [194]

A particle with charge -40.0nC is on the x axis at the point with coordinate x=0 . A second particle, with charge -20.0 nC, is on the x axis at x=0.500 m.

No, there is no point at a finite distance where the electric potential is zero.

Hence, Option D) is correct.

What is electric potential?

Electric potential is the capacity for doing work. In the electrical case, a charge will exert a force on some other charge and the potential energy arises. For example, if a positive charge Q is fixed at some point in space, any other positive charge when brought close to it will experience a repulsive force and will therefore have potential energy.

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To learn more about electric potential, refer to:

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4 0
1 year ago
PLEASEEE HELPPP!!!!
Zigmanuir [339]

Answer: The work is 1863 N*m

Explanation:

We can define work as:

W = F*d

Where F is the force that the mover needs to apply to the refrigerator, and d is the distance that the refrigerator is moved.

To move the refrigerator, the minimal force that the mover needs to do is exactly the friction force (In this case, the refrigerator will move with constant speed).

Then we will have:

F = 230 N

and the distance is 8.1 meters, then the work will be:

W = 230N*8.1 m = 1863 N*m

3 0
2 years ago
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