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zysi [14]
3 years ago
12

A farmer wants to buy a 10 kg bag of fertilizer (organic soil). They have the choice between two merchants. Merchant A sells the

10 kg bag for $10 and the bag indicates that the fertilizer is completely dry. Merchant B sells the 10 kg bag for 8$, and the bag indicates that the fertilizer has a water content of 20%. If the farmer can only use the solid constituents of the bag, which merchant has the better deal?
Engineering
1 answer:
sergejj [24]3 years ago
5 0

Answer:

Since the farmer wants to buy a 10 kg bag of fertilizer, he should buy it from merchant A. However, Merchant A and B are selling at the same price for a unit value. In other words, Both Merchant A and B are selling 1kg of dry fertilizer for $1.

Explanation:

Which merchant has the better deal means which merchant offers the farmer a better deal.

For Merchant A,  10 kg bag = $10

meaning it contains a real 10 kg bag of dry fertilizer which the farmer can use without losing any Kg to drying.

While for Merchant B, 10 kg bag = $8

where the 10kg = 80% dry fertilizer + 20% water content

But the farmer can only use the solid constituents of the bag which means,

Merchant B is giving 80/100 x 10Kg of dry fertilizer for $8

That is, 8kg for $8

Since the farmer wants to buy a 10 kg bag of fertilizer, he should buy it from merchant A. However, Merchant A and B are selling at the same price for a unit value. In other words, Both Merchant A and B are selling 1kg of dry fertilizer for $1.

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40 = 6(X^2) / 4 (tan(180/6)) solve for X
const2013 [10]

Answer:

x = 3.92

Explanation:

The question is given as ;

40 = 6x² / 4 tan { 180/6}

40 = 6x² / 4 tan {30°}

40 = 6x² / 2.309

40 * 2.309 = 6x²

92.38 = 6 x²

92.38/6 = x²

15.40 = x²

√15.40 = x

x = 3.92

3 0
3 years ago
A ball bearing has been selected with the bore size specified in the catolog as 35.000 mm to 35.020 mm. Specify appropriate mini
Fofino [41]

Answer:

the minimum shaft diameter is 35.026 mm

the maximum shaft diameter is 35.042mm

Explanation:

Given data;

D-maximum = 35.020mm and d-minimum = 35.000mm

we have to go through Tables "Descriptions of preferred Fits using the Basic Hole System" so from the table, locational interference fits H7/p6

so From table, Selection of International Trade Grades metric series

the grade tolerance are;

ΔD = IT7(0.025 mm)

Δd = IT6(0.016 mm)

Also from Table "Fundamental Deviations for Shafts" metric series

Sf = 0.026

so  

D-maximum

Dmax = d + Sf + Δd

we substitute

Dmax = 35 + 0.026 + 0.016

Dmax = 35.042 mm

therefore the maximum diameter of shaft is 35.042mm

d-minimum

Dmin = d + Sf

Dmin = 35 + 0.026

Dmin = 35.026 mm

therefore the minimum diameter of shaft is 35.026 mm

8 0
3 years ago
Are there any other controllers like Arduino that run C++ ? And if so, what are the names of them? Is there any used outside of
neonofarm [45]

Answer:

An arduino is just a micro controller. It has a programmable CPU and a memory storage. There're plenty of other microcontrollers out there that does the same thing like the NodeMCU or the Teensy 3. A quick google search should reveal alot more alternatives.

You can pretty much program the arduino using any language. The only thing is that had someone made a compiler to translate the code into the 1's and 0's that can be read by the arduino yet.

As for manufacturing, I think they use their own custom made controller. I haven't seen a company that used an arduino yet.

8 0
3 years ago
Technician A says that synthetic blend oil has the same service life as that of full synthetic oils. Technician B says that conv
stepladder [879]

Answer:

In this case, both technicians are correct because conventional oil wont last as long as full-synthetic or full-synthetic high-mileage oil.   high-mileage or regular full-synthetic? I say go with the full-synthetic high-mileage oil because it can handle more miles than the regular low-mileage oil. it also wont damage ur motor unless ur motor requires  low-mileage oil.

Explanation:

8 0
2 years ago
Assume that a surface-grinding operation is being carried out under the following conditions: D = 250 mm, d 0.1 mm, ys 0.5 m/s a
Misha Larkins [42]

Answer:

modify temperature is lower than by the 0.196 %

Explanation:

given data

D = 250 mm

d = 0.1 mm

v = 0.5 m/s

V = 50 m/s

D = 150 mm

d = 0.1 mm

v = 0.3 m/s

V = 25 m/s

solution

first we get here initial coating condition for temperature change ΔT is

ΔT = A \times D^{1/4} \times d^{3/4}\times \frac{V}{v}^{1/2}    ...............1

put here value for both condition

ΔT = A \times 250^{1/4} \times 0.1^{3/4}\times \frac{50}{0.5}^{1/2}  

ΔT = 7.07 A      ......................2

and

ΔT = A \times 150^{1/4} \times 0.1^{3/4}\times \frac{25}{0.3}^{1/2}  

ΔT = 5.68 A       .......................3

so here percentage change is

percentage change = \frac{5.68 A-7.07 A }{7.07 A }  

percentage change  = - 0.196

so that modify temperature is lower than by the 0.196 %

5 0
3 years ago
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