Answer:
When the denominator of both ratios is the same, adding the ratio is simple. You just add the numbers to the left of the colon (this number is called the Ratio Numerator)xplanation:
Answer:
Having a planner gives students freedom to plan, organize and keep track of their work to the best of their abilities and requirements. This has a dual benefit in that it increases the student's accountability to the commitments planned as well as provides them with a structure that contributes to their success.
Explanation:
In astronomy circumpolar constellations are those ones which never set from viewer's perspective like ursa minor, cassiopiea etc.
Because of the rotation of the Earth and its orbit around the Sun, we divide the stars and constellations into two groups. Some stars and constellations never rise nor set, and they are called circumpolar. All the rest are divided into seasonal stars and constellations. Which stars and constellations will be circumpolar and which seasonal depends on your latitude.
Answer: 40 Newton
Explanation:
Mass of baseball = 20 kg
Velocity of baseball = 20 m/s.
Time taken for throwing = 10 seconds
Since acceleration is the rate of change of velocity per unit time
i.e Acceleration = velocity / time taken
Acceleration = (20 m/s / 10seconds)
Acceleration = 2m/s^2
Now, force required to throw the baseball is a product of mass and acceleration
i.e Force = Mass x acceleration
Force = 20 kg x 2m/s^2
Force = 40Newton
Thus, 40 newton of force is required to throw baseball to reach the plate
Answer:
U = 30 m/s
a = 3 m/s²
Explanation:
"A car accelerating uniformly from rest reaches a maximum speed of U in 10 s. It then moves with that speed for an additional 20 s. The distance covered by the car in the 30 s interval is 750 m. Find U and the acceleration of the car in the first 10 s."
During the first 10 s:
v₀ = 0 m/s
v = U m/s
t = 10 s
The distance covered in this time is the average velocity times time:
Δx = ½ (v + v₀) t
Δx = ½ (U + 0) (10)
Δx = 5U
The distance covered in the next 20 seconds is speed times time:
Δx = 20U
The total distance is 750 m:
5U + 20U = 750
25U = 750
U = 30 m/s
The acceleration during the first 10 seconds is the change in speed over change in time.
a = Δv / Δt
a = (30 m/s − 0 m/s) / 10 s
a = 3 m/s²