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3 years ago

Calculating net force

Physics

1 answer:

aleksandr82 [10.1K]3 years ago

8 0

Answer:

0N.

Explanation:

Net force is the sum total of forces acting on an object.

The Fn which is the net force is

450+ (-250) + (-600)+ 600+ 0 + 250 + (-450)

= 450-250+(-600)+ 600+0+250-450

= 0N

The net force is 0

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Read 2 more answers

a 1150 kg car is on a 8.70 hill. using x-y axis tilted down the plane, what is the x-component of the normal force(unit=N)

rodikova [14]

The x-component of the normal force is equal to <u>1706.45 N.</u>

Why?

To solve the problem, and since there is no additional information, we can safely assume that the x-axis is parallalel to the hill surface and the y-axis is perpendicular to the x-axis. Knowing that, we can calculate the components of the normal force (or weight for this case), using the following formulas:

$N_{x}=W*Sin(\alpha)=mg*Sin(\alpha)\\\\N_{y}=W*Cos(\alpha)=mg*Cos(\alpha)$

Now, using the given information, we have:

$mass=m=1150Kg\\\alpha=8.70\°\\g=9.81\frac{m}{s^{2}}$

Calculating, we have:

$N_{x}=mg*Sin(\alpha)$

$N_{x}=1150Kg*9.81\frac{m}{s^{2}}*Sin(8.70\°)\\\\N_{x}=11281.5\frac{Kg.m}{s^{2} }*Sin(8.70\°)=1706.45\frac{Kg.m}{s^{2} }=1706.45.23N$

Hence, we have that the x-component of the normal force is equal to <u>1706.45 N.</u>

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4 years ago

Children in a tree house lift a small dog in a basket 4.90m up to their house. If it takes 201J of work to do this, what is the

scZoUnD [109]

Answer:

4.18 kg.

Explanation:

Work done: Work is said to be done when ever a force move a body through a given distance. The S.I unit of work done is Joules (J)

Mathematically, work done is expressed as

W' = F×d.................... Equation 1

Where W' = work done, F = force , d = distance.

making F the subject of the equation,

F = W'/d............................. Equation 2

Note: The force need to lift the small dog n a basket = combined weight of the dog ans the basket.

Therefore,

W = F

Where W = combined weight of the dog and the basket.

Also

W = Mg

M = W/g............................. Equation 3

Where M = combined mass of the dog and the basket, g = acceleration due to gravity.

Given: W' = 201 J, d = 4.90 m.

Substitute into equation 2

F = 201/4.9

F = 41.02 N.

Since F = W = 41.02 N and g = 9.81 m/s²

Substitute these values into equation 3

M = 41.02/9.81

M = 4.18 kg.

Thus the combined mass of the dog and the basket = 4.18 kg.

4 0

3 years ago