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3 years ago

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To balance a chemical reaction you can list all the atoms on the right and left, then count, and add coefficients until the reac

tion is balanced. Look at the reaction below. Choose the picture that shows a balanced chemical reaction for the reaction below.

1 answer:

IrinaVladis [17]3 years ago

7 0

Answer:

I think option 3 is correct

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How many metals are on the periodic table?

sergey [27]

There are 91 metals on the periodic table.

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3 years ago

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Acetylene reacts with oxygen to form carbon dioxide and water according to the following unbalanced reaction:

Lelechka [254]

Answer:

Mass of excess reactant leftover after reaction is complete = 34.2 g $\mathrm{C}_{2} \mathrm{H}_{2}$ .

Explanation:

Acetylene reacts with oxygen to form carbon dioxide and water, equation given is unbalanced

$\mathrm{C}_{2} \mathrm{H}_{2}(\mathrm{g})+\mathrm{O}_{2}(\mathrm{g}) \rightarrow \mathrm{CO}_{2}(\mathrm{g})+\mathrm{H}_{2} \mathrm{O}(\mathrm{g})$

Firstly equation is balanced:

$2 \mathrm{C}_{2} \mathrm{H}_{2}(\mathrm{g})+5 \mathrm{O}_{2}(\mathrm{g}) \rightarrow 4 \mathrm{CO}_{2}(\mathrm{g})+2 \mathrm{H}_{2} \mathrm{O}(\mathrm{g})$

$\text { Moles of } \mathrm{CO}_{2} \text { from } \mathrm{C}_{2} \mathrm{H}_{2}$

$\text { Molar mass of } \mathrm{C}_{2} \mathrm{H}_{2} \text { is } 26.04 \mathrm{g} / \mathrm{mol}$

$\text { Moles of } \mathrm{C}_{2} \mathrm{H}_{2}=38.7 \mathrm{gm} \mathrm{C}_{2} \mathrm{H}_{2} \times \frac{1 \mathrm{mol} c_{2} \mathrm{H}_{2}}{26.04 \mathrm{gm} \mathrm{c}_{2} \mathrm{H}_{2}}=1.48 \mathrm{mol} \mathrm{C}_{2} \mathrm{H}_{2}$

$1.48 \mathrm{mol} \mathrm{C}_{2} \mathrm{H}_{2} \times \frac{4 \mathrm{mol} \mathrm{Co}_{2}}{2 \mathrm{mol} C_{2} \mathrm{H}_{2}}=2.96 \mathrm{mol} \mathrm{CO}_{2}$

$\text { Moles of } \mathrm{CO}_{2} \text { from } \mathrm{O}_{2}$ :

$\text { Molar mass of } \mathrm{O}_{2} \text { is } 32.00 \mathrm{g} / \mathrm{mol}$

$\text { Moles of } \mathrm{O}_{2}=13.7 \mathrm{gm} \mathrm{O}_{2} \times \frac{1 \mathrm{mol} O_{2}}{32.00 \mathrm{gm} 0_{2}}=0.428 \mathrm{mol} \mathrm{O}_{2}$

$\text { Here we come to know that } 4 \mathrm{mol} \mathrm{CO}_{2} \equiv 5 \mathrm{mol} \mathrm{O}_{2}, \text { hence }$

$0.428 \mathrm{mol} \mathrm{O}_{2} \times \frac{4 \mathrm{mol} \mathrm{co}_{2}}{5 \mathrm{mol} O_{3}}\left(4 \mathrm{mol} \mathrm{CO}_{2}\right) /\left(5 \mathrm{mol} \mathrm{O}_{2}\right)=0.3424 \mathrm{mol} \mathrm{CO}_{2}$

Here we come to know O2 is limiting reactant as it gives smaller amount of $\mathrm{CO}_{2}$ So $\mathrm{C}_{2} \mathrm{H}_{2}$ is excess reactant.

Mass of excess reactant utilized:

$0.428 \mathrm{mol} \mathrm{O}_{2} \times \frac{2 \mathrm{mol} C_{2} \mathrm{H}_{2}}{5 \mathrm{mol} O_{2}}=0.1712 \mathrm{mol} \mathrm{C}_{2} \mathrm{H}_{2}$

$0.1712 \mathrm{mol} \mathrm{C}_{2} \mathrm{H}_{2} \times \frac{26.04 \mathrm{gm} \mathrm{c}_{2} \mathrm{H}_{2}}{1 \mathrm{mol} C_{2} \mathrm{H}_{2}}=4.45 \mathrm{gm} \mathrm{C}_{2} \mathrm{H}_{2}$

Mass of excess reactant leftover after reaction is complete:

$38.7 \mathrm{gm} \mathrm{C}_{2} \mathrm{H}_{2}-4.45 \mathrm{gm} \mathrm{C}_{2} \mathrm{H}_{2}=34.2 \mathrm{gm} \mathrm{C}_{2} \mathrm{H}_{2}$ .

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4 years ago

What will happen to convection currents in the mantle if earths interior eventually cools down?

VLD [36.1K]

If the core were to cool completely, the planet would grow cold and dead. It also would get a little dark: Power utilities pull radiant heat from Earth's crust and use it to heat water, the steam from which powers turbines to create electricity.Cooling also could cost us the magnetic shield around the planet created by heat from the core. This shield protects Earth from cosmic radiation. The shield is created by a convection process caused by constantly moving iron. Like the planet itself, Earth's core is constantly spinning. Some scientists think it's moving even faster than the rest of the planet. The friction converts kinetic energy into electrical and magnetic energy that forms the field, which deflects harmful, charged particles emanating from the sun toward the north and south poles. Your welcome :)

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4 years ago

A beaker contains 500 ml of 2.40M KNO3 the beaker is left uncovered so that all of the water evaporates. What mass of KNO3 cryst

telo118 [61]

Answer:

242.4 g

Explanation:

RAM of KNO3=39+14+(16×3)=101

Mass=morality×RAM

101*2.4=242.4

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3 years ago

The formula of an iodate of lanthanum is la(io3)3. what is the formula of the sulfate of lanthanum with the same oxidation numbe

sammy [17]

Iodate has a charge of -1, this means its chemical symbol must be IO3(-1) while Lanthanum is La(+3). Therefore making the compound La(IO3)3.

However sulfate has a chemical symbol of SO4(-2), it has charge of -2, therefore the formula for lanthanum sulfate is:

<span>La2(SO4)<span>3</span></span>

8 0

3 years ago

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