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BigorU [14]
3 years ago
13

Literally do not answer this

Engineering
2 answers:
blondinia [14]3 years ago
6 0

Answer:

i literally didnt read the question until i answered it

Explanation:

please mark this answer as brainliest

Soloha48 [4]3 years ago
3 0

Answer:

grhteqfehjwbhcedhjcehcewhdfheuwigfuiewfgywgfehfehwuifgewuhfehfehhfpewjiofewgyfgejnewjowhuoewhfoefhe

Explanation:

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Nadya [2.5K]

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Simply put, the grade or grading around your house is the level of the ground. The ground level and how it's graded is the deciding factor of where storm water will flow.

Explanation:

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3 years ago
ANSWER PLEASE
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2 years ago
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Base course aggregate has a target density of 121.8 lb/ft3 in place It will be laid down and compacted in a rectangular street r
irakobra [83]

Answer:

total weight of the aggregate = 3594878.28 lbs

Explanation:

given data

density = 121.8 lb/ft³

area =  1000 ft x 60 ft x 6 in = 1000 ft x 60 ft x 0.5 ft

moisture = 3.5 %

compaction = 95%

solution

we get here first volume of the space that is filled with the aggregate that is

volume = 1000 ft x 60 ft x 0.5 ft  = 30,000 cu ft

now we get fill space with aggregate that compact to 95% of dry density.

so we fill space with aggregate of density that is = 95% of 121.8

= 115.71 lb/ cu ft

so now dry weight of aggregate is

dry weight of aggregate = 30,000  × 115.71 = 3471300 lb

when we assume that moisture percentage is by weight

then weight of the moisture in aggregate will be

weight of the moisture in aggregate = 3.56 % of 3471300 lb  

weight of the moisture in aggregate = 123578.28 lbs

and

we get total weight of the aggregate to fill space that is

total weight of the aggregate = 3471300 lb +123578.28 lb

total weight of the aggregate = 3594878.28 lbs

4 0
3 years ago
Q1: The first option should always be to get out safely (RUN)
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Answer:

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