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elena55 [62]
3 years ago
14

Urgent help plzzzzzz?!!!!!!!!!!!

Chemistry
1 answer:
jok3333 [9.3K]3 years ago
3 0

Answer:

Explanation:

For 4 all you have to do is take the -log(H3O+) and then use your PH values to identify if it's acidic or basic

a. 2.06 - acidic

b. 8.4 - basic

c. 6.67 - acidic

d. 5.85 - acidic

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Whenever a continuous bell alarm sounds in the Chemistry building:
deff fn [24]

Answer:

C

Explanation:

This is essentially one of the several safety measures in the chemical laboratory. This particular approach is one used in the case of fire eventualities.

A is wrong

This is because in the advent of a fire incident, it is necessary to evacuate the building as a whole. Meeting in the hallway is still within the building which is not the right thing to do when there’s a fire outbreak. Occupants are expected to leave the building immediately

B. Is also wrong. Taking time to pack your belongings might make you be caught in the inferno. It is expected that you leave the building at once

4 0
3 years ago
Calculate the number of moles of magnesium, chlorine, and oxygen atoms in 3.50 moles of magnesium
Firdavs [7]

Answer:

n_{Mg}=3.50molMg\\\\ n_{Cl}=7.00molCl\\\\n_O=28.0molO

Explanation:

Hello there!

In this case, according to the given information it turns out possible for us to realize that one mole of the given compound, Mg(ClO₄)₂, has one mole of Mg, two moles of Cl and eight moles of O; thus, we proceed as follows:

n_{Mg}=3.50molMg(ClO_4)_2*\frac{1molMg}{1molMg(ClO_4)_2}=3.50molMg\\\\ n_{Cl}=3.50molMg(ClO_4)_2*\frac{2molCl}{1molMg(ClO_4)_2}=7.00molCl\\\\n_O=3.50molMg(ClO_4)_2*\frac{8molO}{1molMg(ClO_4)_2}=28.0molO

Best regards!

3 0
3 years ago
The element in Group 14 Period 4 has how many neutrons and is it a metal, nonmetal, metalloid or noble gas.
monitta

Number of neutrons=41, and it is metalloid

<h3>Further explanation</h3>

Group 14⇒valence electron = 4(ns²np²)

Period 4⇒n=4

So electron configuration of the element :

1s², 2s², 2p⁶, 3s², 3p⁶, 4s², 3d¹⁰, 4p² = 32 electron=atomic number

The element with atomic number 32, which is in period 4 and group 14 is Ge-Germanium

There are seven elements that can be classified as metalloids, namely boron (B), silicon (Si), germanium (Ge), arsenic (As), antimony (Sb), tellurium (Te), and polonium (Po).

While the mass number: 73

So the number of neutrons = mass number-atomic number

\tt 73-32=41

8 0
3 years ago
Which of the following is an inorganic compound?<br> AgNO3<br> C6H12<br> СНОН<br> C₂H7N
Lemur [1.5K]

Answer:

AgNO3

Explanation:

Silver nitrate (AgNO3) is an inorganic compound. Organic compounds usually have 1+ C.

4 0
3 years ago
How did Robert Whitaker change dassification?
tester [92]

Answer:

created an organizational hierarchy

Explanation:

3 0
3 years ago
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