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Alchen [17]
4 years ago
15

What kind of friction occurs when moving parts have ball bearings

Physics
2 answers:
Oksanka [162]4 years ago
7 0

Answer: Rolling friction

Explanation:

Rolling friction is said to act when an object rolls over a surface. Machines often have moving parts. These moving parts roll over each other as the machine works. Ball bearings are commonly used to reduce friction between the two surfaces in contact as the machine parts roll over each other. This is a typical example of rolling friction as applied to machine parts.

ASHA 777 [7]4 years ago
7 0

Answer:

Rolling friction.

Explanation:

Rolling friction is the force resisting the motion when a body ( such as a ball, tires, wheel) rolls on a surface. It is applicable for bodies whose point of contact keeps changing. It is the force that opposes the motion of a body which is rolling over the surface of another.

Rolling resistance, sometimes called rolling friction or rolling drag, is the force resisting the motion when a body rolls on a surface. It is mainly caused by non-elastic effects; that is, not all the energy needed for deformation of the wheel, roadbed, etc. is recovered when the pressure is removed.

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Read 2 more answers
0.160-kg hockey puck is moving on an icy, frictionless, horizontal surface. At t 0, the puck is moving to the right at 3.00 m/s.
balandron [24]

Answer: (a)10.812\ m/s\ (b)\ 0.75\ m/s\ \text{left}

Explanation:

Given

Mass of hockey puck m=0.160\ kg

Initial velocity of hockey puck is u=3\ m/s

First a horizontal force of 25\ N is applied to the right for 0.05\ s

acceleration associated with it is

\Rightarrow a=\dfrac{25}{0.160}\\\\\Rightarrow a=156.5\ m/s^2

Using equation of motion i.e.

\Rightarrow v=u+at\\\Rightarrow v=3+156.25\times 0.05\\\Rightarrow v=3+7.812\\\Rightarrow v=10.812\ m/s

(b) When a force of 12\ N is applied for 0.05s

Using equation of motion i.e.

\Rightarrow v=3-\dfrac{12}{0.160}\times 0.05\\\\\Rightarrow v=3-75\times 0.05\\\Rightarrow v=3-3.75\\\Rightarrow v=-0.75\ m/s\\\Rightarrow v=0.75\ \text{towards left}

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3 years ago
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