<h2><em>Dell realizes that their ultimate success lies with the success of their supply chainand its ability to generate supply chain surplus. If Dell was to view supply chainoperations as a zero sum game, they would lose their competitive edge as their suppliers’ businesses struggled. Dell’s profit gained at the expense of their supplychain partners would be short lived. Just as a physical chain is only as strong as itsweakest link, the supply chain can be successful only if all members cooperateand focus on a global optimum rather than many local optima.</em></h2><h2><em></em></h2><h2><em></em></h2><h2><em>HOPE IT HELPS (◕‿◕✿)</em></h2>
Answer:
She was known for her work on X-ray diffraction images of DNA, which led to the discovery of the DNA double helix for which Francis Crick, James Watson, and Maurice Wilkins shared the Nobel Prize in Physiology or Medicine in 1962.
Explanation:
Answer:
135 hour
Explanation:
It is given that a carburizing heat treatment of 15 hour will raise the carbon concentration by 0.35 wt% at a point of 2 mm from the surface.
We have to find the time necessary to achieve the same concentration at a 6 mm position.
we know that 
where x is distance and t is time .As the temperature is constant so D will be also constant
So 
then 
we have given 
and we have to find 
putting all these value in equation
so 
Answer:
Explanation:
For pressure gage we can determine this by saying:
The closed tank with oil and air has a pressure of P₁ and the pressure of oil at a certain height in the U-tube on mercury is p₁gh₁. The pressure of mercury on the air in pressure gauge is p₂gh₂. The pressure of the gage is P₂.
We want to work out P₁-P₂: Heights aren't given so we can solve it in terms of height: assuming h₁=h₂=h
Answer:
import java.util.Scanner;
public class FindMatchValue {
public static void main (String [] args) {
Scanner scnr = new Scanner(System.in);
final int NUM_VALS = 4;
int[] userValues = new int[NUM_VALS];
int i;
int matchValue;
int numMatches = -99; // Assign numMatches with 0 before your for loop
matchValue = scnr.nextInt();
for (i = 0; i < userValues.length; ++i) {
userValues[i] = scnr.nextInt();
}
/* Your solution goes here */
numMatches = 0;
for (i = 0; i < userValues.length; ++i) {
if(userValues[i] == matchValue) {
numMatches++;
}
}
System.out.println("matchValue: " + matchValue + ", numMatches: " + numMatches);
}
}
