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otez555 [7]
3 years ago
8

if an object is projected upwards with an angle 30 to the horizontal and its initial velocity is 20 m/s, its maximum height= ? (

consider g= 10m/s^2 )
Physics
1 answer:
Veronika [31]3 years ago
6 0

Answer:

h_m=5 \ m

Explanation:

<u>Projectile Motion </u>

It's the type of motion that experiences an object projected near the Earth's surface and moves along a curved path under the action of gravity.

The maximum height hm is reached when the vertical component of the velocity is 0. It can be calculated as follows:

\displaystyle h_m=\frac{v_o^2\cdot \sin^2\theta}{2g}

Where:

vo = initial speed of the object

θ   = initial launch angle

g   = acceleration of gravity (10\ m/s^2)

The object is projected with an angle of θ=30° and an initial speed of vo=20 m/s. The maximum height is:

\displaystyle h_m=\frac{20^2\cdot \sin^2 30^\circ}{2*10}

\displaystyle h_m=\frac{400\cdot 0.5^2}{20}

\boxed{h_m=5 \ m}

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