Question

if an object is projected upwards with an angle 30 to the horizontal and its initial velocity is 20 m/s, its maximum height= ? ( consider g= 10m/s^2 )

Answer 1

Answer:

$h_m=5 \ m$

Explanation:

Projectile Motion

It's the type of motion that experiences an object projected near the Earth's surface and moves along a curved path under the action of gravity.

The maximum height hm is reached when the vertical component of the velocity is 0. It can be calculated as follows:

$\displaystyle h_m=\frac{v_o^2\cdot \sin^2\theta}{2g}$

Where:

vo = initial speed of the object

θ   = initial launch angle

g   = acceleration of gravity ($10\ m/s^2$)

The object is projected with an angle of θ=30° and an initial speed of vo=20 m/s. The maximum height is:

$\displaystyle h_m=\frac{20^2\cdot \sin^2 30^\circ}{2*10}$

$\displaystyle h_m=\frac{400\cdot 0.5^2}{20}$

$\boxed{h_m=5 \ m}$