To solve this problem it is necessary to apply the concepts related to the flow as a function of the volume in a certain time, as well as the potential and kinetic energy that act on the pump and the fluid.
The work done would be defined as
Where,
PE = Potential Energy
KE = Kinetic Energy
Where,
m = Mass
g = Gravitational energy
h = Height
v = Velocity
Considering power as the change of energy as a function of time we will then have to
The rate of mass flow is,
Where,
= Density of water
A = Area of the hose 
The given radius is 0.83cm or 
m, so the Area would be
We have then that,
Final the power of the pump would be,
Therefore the power of the pump is 57.11W
Answer:
Yes labor is required therefor jobs like cashier, and other low skill labor jobs I'll not be required
Explanation:
The mass is 222g. No, it is less than 1kg. There are 1000 grams in a kilogram so it would be 0.222kg. Hope this Helps :D
Answer: For 18 the inch is longer im not sure by how much, for 19 the the kilogram is 2.2 times heavier than a pound, QUART IS A LITTLE LESS THAN A LITER. ... An easy way to figure from liters to gallons, for example, is that a quart is a little less than a liter and 4 liters is a little more than 1 gallon. To be exact, 1 liter is 0.264 gallon (a little more than a quart), and 4 liters is 1.06 gallons, 30°C or 30°F? Correct answer: the table shows that 30°C is about 86°F, which is warmer than 30°F. And sorry Im not sure how to do the rest
Explanation:
Answer:Given mass = 4.1kg
Radius = 0.0117m
Velocity V = 8.4m/s
Coefficient of friction = 0.25
Explanation: Below is an attached solution to the problem stated above.
1. The angular acceleration is equal to 524rad/s^2
2. The linear acceleration is equal to 2.45m/s^2
3.the time it takes the ball to begin rolling = 0.98s
4. The distance the ball slides before it begins to roll = 7.05m
