3 years ago

Your help will really be great plz help me

Physics

2 answers:

Finger [1]3 years ago

7 0

Answer:

subtract 20 -5 to get the upthrust

Paul [167]3 years ago

7 0

5 N

Archimedes' Principle

25 N

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LOTS OF POINTSA rocket of mass 40 000 kg takes off and flies to a height of 2.5 km as its engines produce 500 000 N of thrust.

Svetradugi [14.3K]

Answer:

i) E = 269 [MJ] ii)v = 116 [m/s]

Explanation:

This is a problem that encompasses the work and principle of energy conservation.

In this way, we establish the equation for the principle of conservation and energy.

$E_{k1}+W_{1-2}=E_{k2}\\where:\\E_{k1}= kinetic energy at moment 1\\W_{1-2}= work between moments 1 and 2.\\E_{k2}= kinetic energy at moment 2.$

$W_{1-2}= (F*d) - (m*g*h)\\W_{1-2}=(500000*2.5*10^3)-(40000*9.81*2.5*10^3)\\W_{1-2}= 269*10^6[J] or 269 [MJ]$

At that point the speed 1 is equal to zero, since the maximum height achieved was 2.5 [km]. So this calculated work corresponds to the energy of the rocket.

Er = 269*10^6[J]

ii ) With the energy calculated at the previous point, we can calculate the speed developed.

$E_{k2}=0.5*m*v^2\\269*10^6=0.5*40000*v^2\\v=\sqrt{\frac{269*10^6}{0.5*40000} }\\ v=116[m/s]$

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3 years ago

Do you like genetic engineering explain even if there is no answer box still answer in the commets

liubo4ka [24]

Answer:

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Explanation:

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3 years ago

the distance between two points P and Q is 120 m a object goes from point P to q and then returned to P in 1 minute 40 second wh

Naily [24]

Answer:

using a formula

average velocity=total displacement/total time

average velocity=120/1minute40sec

1minute=60sec

60sec+40sec=120sec

average velocity=120m/120sec

average velocity=1m/sec

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3 years ago

when a constant force acts upon an object the acceleration of the object varies inversely with its mass. when a certain constant

solong [7]

Explanation:

When a constant force acts upon an object the acceleration of the object varies inversely with its mass.

$a\propto \dfrac{1}{m}$

$\dfrac{a_1}{a_2}=\dfrac{m_2}{m_1}$

If m₁ = 21 kg, a₁ = 3 m/s², m₂ = 9 kg

We need to find a₂

So,

$a_2=\dfrac{m_1a_1}{m_2}\\\\a_2=\dfrac{21\times 3}{9}\\\\a_2=7\ m/s^2$

So, if mass is 9 kg, its acceleration is 7 m/s².

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3 years ago

A golf ball is launched horizontally at a speed of 11 meters per second and a high of 6.4 m above the ground. How long will it t

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The answer is A.

t = ( 2h / g )^1/2 = ( 2 x 6.4 / 9.8 )^1/2 = 1.14s

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