Complete Question:
When specially prepared Hydrogen atoms with their electrons in the 6f state are placed into a strong uniform magnetic field, the degenerate energy levels split into several levels. This is the so called normal Zeeman effect.
Ignoring the electron spin what is the largest possible energy difference, if the magnetic field is 2.02 Tesla?
Answer:
ΔE = 1.224 * 10⁻²² J
Explanation:
In the 6f state, the orbital quantum number, L = 3
The magnetic quantum number, 
The change in energy due to Zeeman effect is given by:
Magnetic field B = 2.02 T
Bohr magnetron, 
ΔE = 1.224 * 10⁻²² J
Explanation:
sinces : Momentum = velocity × mass
then : 30 = 10 × m and m = 30 ÷ 10 = 3 kg
28 degrees celsius converts to 82.4 degrees in Fahrenheit :)
The speed of a wave is determined by the product of the frequency and the wavelength; we already have the wavelength and the frequency, so all we need to do is multiply them by each other and use our proper unit of measure.
Velocity (speed) = Frequency x Wavelength
V = 250 x 6
V = 1500
Your answer is 1500 m/s.
I hope this helps!
Explanation:
Given that,
Wavelength of the photon, 
Work function of the metal, 
We need to find the maximum kinetic energy of the ejected electrons. It can be calculated using Einstein's photoelectric equation as :
or
So, the maximum kinetic energy of the ejected electrons is 3 ev. Hence, this is the required solution.
