Electric force is present between proton and electron of an atom.
<h3>What is the attractive force present between a proton and electron?</h3>
The attractive force between the electrons and the proton of the nucleus is called the electric force. This force attract electron towards the nucleus so that it can't escape from the atom easily so this force is very important for the atom.
<h3>How an atom of this element changes when it forms an ionic bond?</h3>
An atom of this element changes when it forms an ionic bond because the number of electron decreases due to losing of electron in order to get stability. We know that ionic bond forms between atoms when electron is lost or gain by the atom.
So we can conclude that electric force is present between proton and electron of an atom.
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Answer:
Gravitation
Explanation:
Gravity, also called gravitation, in mechanics, the universal force of attraction acting between all matter. ... On Earth all bodies have a weight, or downward force of gravity, proportional to their mass, which Earth's mass exerts on them. Gravity is measured by the acceleration that it gives to freely falling objects.
Answer:
The acceleration will be 140 meter per second
Explanation:
Force F = mass m × acceleration a
If F = 42 N and m = 0.30 kg
Then acceleration a = F/m
a = 42/0.30
a = 140 m/s
Answer:
a = -0.33 m/s² k^
Direction: negative
Explanation:
From Newton's law of motion, we know that;
F = ma
Now, from magnetic fields, we know that;. F = qVB
Thus;
ma = qVB
Where;
m is mass
a is acceleration
q is charge
V is velocity
B is magnetic field
We are given;
m = 1.81 × 10^(−3) kg
q = 1.22 × 10 ^(−8) C
V = (3.00 × 10⁴ m/s) ȷ^.
B = (1.63T) ı^ + (0.980T) ȷ^
Thus, since we are looking for acceleration, from, ma = qVB; let's make a the subject;
a = qVB/m
a = [(1.22 × 10 ^(−8)) × (3.00 × 10⁴)ȷ^ × ((1.63T) ı^ + (0.980T) ȷ^)]/(1.81 × 10^(−3))
From vector multiplication, ȷ^ × ȷ^ = 0 and ȷ^ × i^ = -k^
Thus;
a = -0.33 m/s² k^
