The combustion of 30.0 g of glucose at room temperature and pressure produces 24.0 L of carbon dioxide.
<h3>What is combustion?</h3>
It is a reaction in which a substance burns with oxygen to form carbon dioxide and water.
Let's consider the combustion of glucose.
C₆H₁₂O₆ + 6 O₂ ⇒ 6 CO₂ + 6 H₂O
First, let's convert 30.0 g of glucose to moles using its molar mass.
30.0 g × 1 mol/180.16 g = 0.167 mol
The molar ratio of C₆H₁₂O₆ to CO₂ is 1:6. The moles of carbon dioxide produced are:
0.167 mol Glucose × (6 mol CO₂/1 mol Glucose) = 1.00 mol CO₂
1 mol of an ideal gas at room temperature and pressure occupies 24.0 L.
The combustion of 30.0 g of glucose at room temperature and pressure produces 24.0 L of carbon dioxide.
Learn more about combustion here: brainly.com/question/9425444
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Answer:
First Blank: 656.3 kJ
Second Blank: Endothermic
Explanation:
Edge 21'
The first part of Dalton's model is that all matter is made of atoms, and these atoms are indivisible.
The second part of this model is that atoms of an element have identical masses and identical propertes.
At last, the third part of Dalton's model is that all compounds are formed by two or more different type of atoms combined.