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Natasha2012 [34]
3 years ago
7

If the index of refraction for a certain glass is 1.5, and the angle of refraction is 15 degrees for a ray of light

Physics
1 answer:
LiRa [457]3 years ago
4 0

Answer:

\theta_i = 23^o

Explanation:

The refractive index of a medium is given by the following formula:

\eta = \frac{Sin\theta_i}{Sin\theta_r}

where,

η = refractive index = 1.5

\theta_i = angle of incidence = ?

\theta_r = angle of refraction = 15°

Therefore,

1.5 = \frac{Sin\theta_i}{Sin15^o}\\\\Sin\theta_i=(1.5)Sin15^o\\\\\theta_i = Sin^{-1}(0.388)\\\\

\theta_i = 23^o

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The magnitude of the magnetic dipole moment of the bar magnet is 1.2 Am²

<h3> Magnetic dipole moment of the bar magnet</h3>

The magnitude of the magnetic dipole moment of the bar magnet at distance from its axis is calculated as follows;

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m = (4π x 0.1³ x 2.4 x 10⁻⁴)/(2 x 4π x 10⁻⁷)

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The complete question is below:

What is the magnitude of the magnetic dipole moment of the bar magnet from 0.1 m of its axis and magnetic field strength of 2.4 x 10⁻⁴ T.

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1 year ago
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3 years ago
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Tom kicks a soccer ball on a flat, level field giving it an initial speed of 20 m/s at an angle of 35 degrees above the horizont
SVEN [57.7K]

Answer:

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Explanation:

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R = \frac{u^{2} \times Sin 2\theta }{g}

R = \frac{20^{2} \times Sin 2 \times 35}{9.8}

R = 38.35 m

(d) It hits with the same speed at the initial speed.

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3 years ago
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