The magnitude of the magnetic dipole moment of the bar magnet is 1.2 Am²
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Magnetic dipole moment of the bar magnet</h3>
The magnitude of the magnetic dipole moment of the bar magnet at distance from its axis is calculated as follows;

where;
- B is magnetic field
- m is dipole moment
- μ is permeability of free space
m = (4π x 0.1³ x 2.4 x 10⁻⁴)/(2 x 4π x 10⁻⁷)
m = 1.2 Am²
The complete question is below:
What is the magnitude of the magnetic dipole moment of the bar magnet from 0.1 m of its axis and magnetic field strength of 2.4 x 10⁻⁴ T.
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Answer:
(a) 2.34 s
(b) 6.71 m
(c) 38.35 m
(d) 20 m/s
Explanation:
u = 20 m/s, theta = 35 degree
(a) The formula for the time of flight is given by


T = 2.34 second
(b) The formula for the maximum height is given by


H = 6.71 m
(c) The formula for the range is given by


R = 38.35 m
(d) It hits with the same speed at the initial speed.
Choices 1, 2, and 4 . . . . . Yes
Choices 3 and 5 . . . . . No
Answer:
It is important to be able to separate mixtures to obtain a desired component from the mixture and to be able to better understand how each component.
Explanation: