The Stern-Gerlach experiment of 1922 established that each individual

Two large parallel conducting plates carrying opposite charges of equal magnitude are separated by 2.20 cm. Part A If the surfac

alukav5142 [94]

Answer:

5308.34 N/C

Explanation:

Given:

Surface density of each plate (σ) = 47.0 nC/m² = $47\times 10^{-9}\ C/m^2$

Separation between the plates (d) = 2.20 cm

We know, from Gauss law for a thin sheet of plate that, the electric field at a point near the sheet of surface density 'σ' is given as:

$E=\dfrac{\sigma}{2\epsilon_0}$

Now, as the plates are oppositely charged, so the electric field in the region between the plates will be in same direction and thus their magnitudes gets added up. Therefore,

$E_{between}=E+E=2E=\frac{2\sigma}{2\epsilon_0}=\frac{\sigma}{\epsilon_0}$

Now, plug in $47\times 10^{-9}\ C/m^2$ for 'σ' and $8.85\times 10^{-12}\ F/m$ for $\epsilon_0$ and solve for the electric field. This gives,

$E_{between}=\frac{47\times 10^{-9}\ C/m^2}{8.854\times 10^{-12}\ F/m}\\\\E_{between}= 5308.34\ N/C$

Therefore, the electric field between the plates has a magnitude of 5308.34 N/C

5 0

3 years ago

8. A 2 kg flower pot weighing 20 N falls from a window ledge.

Alina [70]

The force of the air resistance is 4 N.

The given parameters;

mass of the flower pot, m = 2 kg

weight of the flower pot, W = 20 N

Let the air resistance = F

Apply Newton's second law of motion to determine the force of the air resistance acting upward to oppose the motion of the pot falling downwards.

$\Sigma F = ma\\\\W - F = ma\\\\a = \frac{W - F}{m} \\\\8 = \frac{20 - F}{2} \\\\20 - F = 16\\\\F = 20 - 16\\\\F = 4 \ N$

Thus, the force of the air resistance is 4 N.

Learn more here: brainly.com/question/19887955

8 0

3 years ago

A car drives at a velocity of 6.8 m/s for 250 seconds. How far did it travel?

Leno4ka [110]

$\qquad \qquad\huge \underline{\boxed{\sf Answer}}$

Here's the solution ~

As we know, Displacement =

$\qquad \sf \dashrightarrow \: velocity \times time$

$\qquad \sf \dashrightarrow \: 6.8 \times 250$

$\qquad \sf \dashrightarrow \: 1700 \: m$

$\qquad \sf \dashrightarrow \: 1.7 \: km$

The car travelled 1700 meters ( 1.7 km )

8 0

3 years ago

Two moles of an ideal monatomic gas go through the cycle abc. For the complete cycle, 800 J of heat flows out of the gas. Proces

KiRa [710]

a) Sketches of all possible pv-diagrams for the cycle are attached below

b) The work W $_{ac}$ for the process Ca is : 2462.8 J

Given data :

Amount of heat flowing out = 800 J

Ta = 200 K

Tb = 300 K

R = 800

B) Determine the work W for the process Ca

Wₐs = -pdv

= - [ pVb - pVa ] ---- ( 1 )

note : pVb = nRTb , pVa = nRTa

Equation ( 1 ) becomes

= -nR [ Tb - Ta ]

= - 2(8.314 ) [ 300 - 200 ]

= - 1662.87

given that W $_{bs}$ = 0 which is isochonic

dv = 0 ( cyclic process ) = d∅ - dw

∴ 0 = 800 - ( Wₐs + W $_{ac}$ )

Therefore : W $_{ac}$ = 800 + 1662.8 = 2462.8 J

Hence we can conclude that the work W for the process Ca = 2462.8 J

Learn more about Pv diagrams : brainly.com/question/25401637

Download pdf

3 0

3 years ago

How many milligrams are equal to 8 grams?

Andre45 [30]

Answer:

it should be 8,000

Explanation:

because if you multiply the mass value by 1000, you will get 8,000

:):):):)

6 0

4 years ago