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Lena [83]
3 years ago
11

"I could feel his anguish" what could be the anguish​

Physics
1 answer:
sergey [27]3 years ago
3 0

Answer:

yeah

Explanation:

the answer is right.

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An object weighing 1.840 kg has a volume of 0.0015 m3. What is the density of the object in g/cm3?
olga_2 [115]

Answer:

1.22gcm³

Explanation:

D = mass/ volume

Mass=1.840kg = 1,840g

1000g = 1kg

1.840kg= x(g)

X(g) = 1.840/1000

= 1840g

Volume = 0.0015m³= 1,500cm³

1m³= 1000,000cm³.

0.0015m³= x(cm³)

X(cm³) = 1000,000×0.0015

X(cm³)= 1500.

Since density is mass/volume, now impute your data's

D=m/v

D=1840/1500

1.22g/cm³

5 0
2 years ago
WILL GIVE BRAINLIEST AND 5 STARS.
Zolol [24]
The right answer is b) copper
8 0
3 years ago
Read 2 more answers
A metal begins to emit electrons, as measured in an apparatus similar to the one Hertz used, when exposed to light at a waveleng
balandron [24]

Answer : The work function of this metal is, 5.81\times 10^{-19}J

Explanation : Given,

Wavelength of light = 342nm=342\times 10^{-9}m

Formula used :

E=h\nu_o=\frac{hc}{\lambda}

where,

E = work function of metal

h = Planck's constant = 6.626\times 10^{-34}Js

\nu_o = threshold frequency

\lambda = wavelength of light

c = speed of light = 3\times 10^8m/s

Now put all the given values in this formula, we get the value of work function of this metal.

E=\frac{hc}{\lambda}

E=\frac{(6.626\times 10^{-34}Js)\times (3\times 10^8m/s)}{(342\times 10^{-9}m)}

E=5.81\times 10^{-19}J

Therefore, the work function of this metal is, 5.81\times 10^{-19}J

7 0
3 years ago
Night vision glasses detect energy given off by objects as
shepuryov [24]
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8 0
3 years ago
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A 4500 kg car is pushed by 3 boys who exert a force totaling 1500 N. When the boys begin to push the car it is traveling 4.5 m/s
Brilliant_brown [7]

Answer:

The velocity of the car after 3 seconds is 5.5 m/s

Explanation:

Mathematically, we can get the acceleration of the car first;

F = m•a

where m is the mass, F is the applied force and a is the acceleration

from the question;

F = 1500 N , m = 4500 kg and a = ?

By rewriting the formula;

a = F/m

a = 1500/4500 = 1/3 m/s^2

Now to get the velocity of the car after 3 seconds;

Mathematically;

V = U + at

where V is the final

velocity, U is the initial velocity,

From the question, we are trying to get V;

where U = 4.5 m/s

a = 1/3 m/s^2 and t = 3 seconds

Thus;

V = 4.5 + (1/3)(3)

V = 4.5 + 1

V = 5.5 m/s

7 0
2 years ago
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