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Aleks [24]
3 years ago
14

Which conclusion is best supported by the data?

Physics
2 answers:
sattari [20]3 years ago
8 0

Answer: b

Explanation: the chart

dimulka [17.4K]3 years ago
7 0

Answer:

I think its A

Explanation:

If you think about it the solar panels work the whole year round. hope this helps!

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Nancy needs to do a scientific investigation for her class. She is interested in pottery, plants, and basketball. Which of the f
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I believe that the answer is A hope this helped.
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3 years ago
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Sam stands on a 20 m high cliff and throws a 45 g rock with an initial velocity of 5 m/s [forward] to the water below. Use the c
storchak [24]

Answer:

v = 12.52 [m/s]

Explanation:

To solve this problem we must use the energy conservation theorem. Which tells us that potential energy is transformed into kinetic energy or vice versa. This is more clearly as the potential energy decreases the kinetic energy increases.

Ep = Ek

where:

Ep = potential energy [J] (units of joules]

Ek = kinetic energy [J]

Ep = m*g*h

where:

m = mass of the rock = 45 [g] = 0.045 [kg]

g = gravity acceleration = 9.81 [m/s²]

h = elevation = (20 - 12) = 8 [m]

Ek = 0.5*m*v²

where:

v = velocity [m/s]

The reference level of potential energy is taken as the ground level, at this level the potential energy is zero, i.e. all potential energy has been transformed into kinetic energy. In such a way that when the Rock has fallen 12 [m] it is located 8 [m] from the ground level.

m*g*h = 0.5*m*v²

v² = (g*h)/0.5

v = √(9.81*8)/0.5

v = 12.52 [m/s]

5 0
3 years ago
In 2.5 S, a Car increases its speed from 20.0m/s to 25.0 m/s what is the acceleration of the car​
Dima020 [189]

Answer:

2 m/s

Explanation:

3 0
3 years ago
What increases the work output of a machine
Ilia_Sergeevich [38]

There are only two things you can do to increase the work output of a machine:


1).  Increase the work INput to the machine.


2).  Make the machine more efficient ... do things like lubricating it better to eliminate some internal friction.

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3 years ago
How much power does it take to lift 30.0 N 10.0 m high in 5.00 s?
Rudik [331]

Power = work/time = (Force times distance)/time

= (30N *10.0m)/5.00s = 300/5 = 60 Watts

7 0
3 years ago
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