1
Explanation:
The value of all conversion factors that are used in dimensional analysis must be 1.
Dimensional analysis is a beautiful and systematic way of converting one unit to another using a simple scientific method in which a conversion factor of 1 is used to multiply the number to be converted.
For example, let us convert 1200kg to g:
We know that;
1000g = 1kg
The conversion factor is;

The above value is the same as 1 since 1kg and 1000g are the same.
Now multiply with 1200kg;
1200kg x
= 1200000g
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The phospholipid head is hydrophilic which means it has an affinity for water. And it is true.
<h3>What is phospholipid , its component and how come it is hydrophilic?</h3>
- Phospholipid contains of a head and a tail , the head part of phospholipid consist of phosphate group and for further clarification the tail part of phospholipid consist of fatty acids.
- As we know already phosphate group that is OH- is negatively charged which clearly which its head is going to be polar .
- Since its polar , its hydrophilic. There is a specific function performed by phosphate group that cannot be filled by other compound present simultaneously.
- Phosphate group grabs a role to provide space to other compounds too.
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Answer:
95.2 - 40.8 = 54.4 g of oxygen
number of moles = mass (g)/ Mr
no. of moles of carbon = 40.8/12 = 3.4
no. of moles of oxygen = 3.4
divide both by smallest value which is 3.4 and you’ll get 1 mole of carbon and 1 mole of oxygen therefore the empirical formula is CO
Explanation:
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Answer
pH=8.5414
Procedure
The Henderson–Hasselbalch equation relates the pH of a chemical solution of a weak acid to the numerical value of the acid dissociation constant, Kₐ. In this equation, [HA] and [A⁻] refer to the equilibrium concentrations of the conjugate acid-base pair used to create the buffer solution.
pH = pKa + log₁₀ ([A⁻] / [HA])
Where
pH = acidity of a buffer solution
pKa = negative logarithm of Ka
Ka =acid disassociation constant
[HA]= concentration of an acid
[A⁻]= concentration of conjugate base
First, calculate the pKa
pKa=-log₁₀(Ka)= 8.6383
Then use the equation to get the pH (in this case the acid is HBrO)
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