Question

Can help me with this circuit question? ​the last word is (cutoff)

Answer 1

Answer:

The answer is "$25\times 10^{-9}$".

Explanation:

Using formula:

$f_c=\frac{1}{2\pi RC}\\\\w_c= 4 \frac{krad}{sec}\\\\w_c=2\pi fc\\\\R=w\\\\c=\frac{1}{w_c\ R}$

  $=\frac{1}{4 \times 10^3 \times 10\times 10^3}\\\\=\frac{1}{40 \times 10^6 }\\\\=0.025 \times 10^{-6 }\\\\=25\times 10^{-9}$