3 years ago

Kevin fixes trucks as a job. The engine is oily. Which set set of equipment should Kevin use to fix the truck?

Engineering

1 answer:

vichka [17]3 years ago

4 0

Answer:

A hammer and a wrench

Explanation:

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Answer:

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Explanation:

For pressure P =0.24 MPa and T_1 = 0 DEGREE, Enthalapy _1 = 248.89 kJ/kg

For pressure P =1 MPa and T_1 = 50 DEGREE, Enthalapy _1 = 280.19 kJ/kg

Heat loss Q = 0.05w

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exit diamter = 1.5 cm

volume of tank will be v = area * velocity

velocity at inlet $= \frac{0.64\60 m/s}{ \frac{\pi}{4} (3\times 10^{-2})^2} = 15.09 m/s$

velocity at outlet $= \frac{0.64\60 m/s}{ \frac{\pi}{4} (1.5\times 10^{-2})^2} = 60.36 m/s$

steady flow energy equation

$E_{IN} = E_{OUT}$

$h_1 + \frac{v_1^2}{2g} +wc = h_2 + \frac{v_2^2}{2g} + 0.05wc$

$248.89 + \frac{15.09^2}{2} + wc = 280.18 + \frac{60.36^2}{2} + 0.05 wc$

solving wc = 1830.64 kJ/kg

wc in KWH

we know that $wc = \dot m wc$

$\dot m = 4.25 kg/m3 \times (0.64/60) m^3/s$

$\dot m = 0.04533 kg/s$

$wc = 0.04533 \times 1830.64 = 82.989 kW$

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