An not sure,, but maybe 24. don't take my word for it
Hey there!
Mn + HI → H₂ + MnI₃
Balance I.
1 on the left, 3 on the right. Add a coefficient of 3 in front of HI.
Mn + 3HI → H₂ + MnI₃
Balance H.
3 on the left, 2 on the right. Multiply everything else by 2.
2Mn + 6HI → H₂ + 2MnI₃
Now we have 6 on the left and 2 on the right. Add a coefficient of 3 in front fo H₂.
2Mn + 6HI → 3H₂ + 2MnI₃
Balance Mn.
2 on the left, 2 on the right. Already balanced.
Our final balanced equation:
2Mn + 6HI → 3H₂ + 2MnI₃
Hope this helps!
Answer:
Explanation:
Hello!
In this case, since the combustion analysis provides us the yielded mass of both water and carbon dioxide, as the sources of hydrogen and carbon in the hydrocarbon, we are able to compute the moles of each via the following mole-mass relationships:
Now, we divide those moles by the fewest ones (those of carbon) in order to compute their subscripts in the empirical formula:
However we need whole numbers, that is why we multiply each subscript by 4 to get 4 for carbon and 5.08 ≅ 5 for hydrogen:
Best regards!
B. sit in the sun
they are cold blooded so they feel how their skin feels
Answer:
45.13 psi
Explanation:
Assuming the volume does not change
P1/T1 = P2/T2 T must be in Kelvin
40/(273.15) = P2/(273.15 + 35) P2 = 45.13 psi